Strictly speaking, x^2 + 2x + 4 doesn't have solutions; if you want solutions, you must equate <span>x^2 + 2x + 4 to zero:
</span>x^2 + 2x + 4= 0. "Completing the square" seems to be the easiest way to go here:
rewrite x^2 + 2x + 4 as x^2 + 2x + 1^2 - 1^2 = -4, or
(x+1)^2 = -3
or x+1 =i*(plus or minus sqrt(3))
or x = -1 plus or minus i*sqrt(3)
This problem, like any other quadratic equation, has two roots. Note that the fourth possible answer constitutes one part of the two part solution found above.
Answer:
-6
Step-by-step explanation:
The equation is in slope intercept form
y = mx+b where m is the slope and b is the y intercept
The y intercept is the value when x = 0
The y value is -6 when the x value is 0
y = -4x+ (-6)
The standard deviation been hiked to the nearest tenth is 17.1
Corresponding angles for parallel lines r and s cut by transversal q. Corresponding angles are congruent angles.
1 and 9
2 and 10
3 and 11
4 and 12
Corresponding angles for parallel lines p and q cut by transversal s. Corresponding angles are congruent angles.
11 and 15
9 and 13
12 and 16
10 and 14
Corresponding angles for parallel lines p and q cut by transversal r. Corresponding angles are congruent angles.
1 and 5
3 and 7
2 and 6
4 and 8
Linear pair theorem. These 2 angles are equal to 180°
∠1 + ∠2 = 180
∠3 + ∠4 = 180
∠9 + ∠10 = 180
∠11 + ∠12 = 180
∠5 + ∠6 = 180
∠7 + ∠8 = 180
∠13 + ∠14 = 180
∠15 + ∠16 = 180
∠1 + ∠3 = 180
∠2 + ∠4 = 180
∠9 + ∠11 =180
∠10 + ∠12 = 180
∠5 + ∠7 = 180
∠6 + ∠8 = 180
∠13 + ∠15 = 180
∠14 + ∠16 = 180
Vertical angles theorem. Vertical angles are congruent.
1 and 4
2 and 3
9 and 12
10 and 11
5 and 8
6 and 7
13 and 16
14 and 15
Step-by-step explanation:
you need too look somewhere else
