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Firlakuza [10]
4 years ago
13

Help ASAP will give BRAINLIEST if answer is right

Mathematics
2 answers:
blondinia [14]4 years ago
6 0

2 1/4

Explanation-

1/2+1/2=2/2-------1 Whole

1/4+1/4=2/4

1+2/4= 1 2/4

3/4+ 1 2/4= 1 5/4= 2 1/4

zalisa [80]4 years ago
5 0

What grade math is this lol

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Find the measure of the missing angles. need help ASAP
pochemuha
Sorry if it’s confusing i tried color coding it

the measure of angle 6 is 71.5 degrees

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3 years ago
Find the distance between A(13,2) and B(7,10)
ICE Princess25 [194]

Answer:

Distance = Square Root ((X2 - X1)^2 + (Y2 - Y1)^2)

Distance = Square Root ((7 -13))^2  + ((10 -2))^2

Distance = Square Root ((-6))^2 + ((8^))2

Distance = Square Root (36 + 64)

Distance = 10

Step-by-step explanation:

8 0
3 years ago
The weather during the day was 5°C. The temperature dropped 8° at night. What was the nighttime temperature? ​
blondinia [14]

Answer:

-3 degrees C

Step-by-step explanation:

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8 0
3 years ago
A survey organization has used the methods of our class to construct an approximate 95% confidence interval for the mean annual
lawyer [7]

Answer:

\bar X = \frac{66000+70000}{2}= 68000

We can estimate the margin of error with this formula:

ME= \frac{Upper -Lower}{2}= \frac{70000-66000}{2}= 2000

And the margin of error is given by:

ME = z_{\alpha/2}\frac{\sigma}{\sqrt{n}}

And we can rewrite the margin of error like this:

ME =z_{\alpha/2}*SE

Where SE= \frac{\sigma}{\sqrt{n}}

For 95% of confidence the critical value is z_{\alpha/2}= \pm 1.96

The Standard error would be:

SE= \frac{ME}{z_{\alpha/2}}= \frac{2000}{1.96}= 1020.408

For 99% of confidence the critical value is z_{\alpha/2}= \pm 2.58

And the new margin of error would be:

ME = 2.58* 1020.408 = 2632.653

And then the interval would be given by:

Lower = 68000- 2632.653 = 65367.347

Upper = 68000+ 2632.653 = 70632.653

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

\bar X represent the sample mean for the sample  

\mu population mean (variable of interest)

s represent the sample standard deviation

n represent the sample size  

Solution to the problem

The confidence interval for the mean is given by the following formula:

\bar X \pm z_{\alpha/2}\frac{\sigma}{\sqrt{n}}   (1)

The 95% confidence interval is given by (66000 , 70000)

We can estimate the mean with this formula:

\bar X = \frac{66000+70000}{2}= 68000

We can estimate the margin of error with this formula:

ME= \frac{Upper -Lower}{2}= \frac{70000-66000}{2}= 2000

And the margin of error is given by:

ME = z_{\alpha/2}\frac{\sigma}{\sqrt{n}}

And we can rewrite the margin of error like this:

ME =z_{\alpha/2}*SE

Where SE= \frac{\sigma}{\sqrt{n}}

For 95% of confidence the critical value is z_{\alpha/2}= \pm 1.96

The Standard error would be:

SE= \frac{ME}{z_{\alpha/2}}= \frac{2000}{1.96}= 1020.408

For 99% of confidence the critical value is z_{\alpha/2}= \pm 2.58

And the new margin of error would be:

ME = 2.58* 1020.408 = 2632.653

And then the interval would be given by:

Lower = 68000- 2632.653 = 65367.347

Upper = 68000+ 2632.653 = 70632.653

7 0
4 years ago
Please solve with explanation. 15 points
stich3 [128]

Answer:

B.

Step-by-step explanation:

It's B since (look at the picture)

7 0
2 years ago
Read 2 more answers
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