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guajiro [1.7K]
3 years ago
14

List 4 ways mitosis works

Biology
2 answers:
Zanzabum3 years ago
6 0
You can do like my teacher teach me but is ridiculous :

I = intherphase
Play = prophase
Monopoly= metaphase
At = Anaphase
The = telophase
Club = cytoquinesis
V125BC [204]3 years ago
5 0
1prophase
2metaphase
3anaphase
4telophase
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Sergeu [11.5K]

Answer:

<em>In biochemistry and pharmacology, receptors are chemical structures, composed of protein, that receive and transduce signals that may be integrated into biological systems</em>

3 0
3 years ago
What two components are often found as part of an enzyme?
alukav5142 [94]
Two components that are very common and often found are:
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7 0
3 years ago
In a population of Mendel's garden peas, the frequency of the dominant A (yellow flower) allele is 80%. Let p represent the freq
DENIUS [597]

Answer:

If the frequency of the dominant allele in the pea population is 0.8, the genotype frequencies in the population would be 0.64 AA, 0.32 Aa, and 0.04 aa.

Explanation:

Hardy-Weinberg equation tells us that:

p2 + 2pq + q2

p2 is the frequency of AA plants

2pq is the frequency of Aa plants, and

q2 the frequency of aa individuals.

A allele in the population is 80%, the frequency is 0.8.

p represent the frequency of A allele. p is 0.8

Therefore calculating for q ( frequency of a allele).

p + q = 1.0

q = 1.0 − p

q = 1.0 − 0.8

q = 0.2

p = 0.8, q = 0.2.

Now we can calculate the predicted frequencies of the different genotypes, remembering that p2 is the frequency of the AA genotype, 2pq is the frequency of the Aa genotype, and q2 the frequency of aa genotype.

p2 = 0.8 x 0.8 = 0.64

2pq = 2 x 0.8 x 0.2 = 0.32

q2 = 0.2 x 0.2 = 0.04.

Thus, we would expect to see genotype frequencies of 0.64 AA, 0.32 Aa, and 0.04 aa in the pea plants.

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3 years ago
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-Hope this helps.
4 0
3 years ago
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