Answer:
First choice.
Step-by-step explanation:
The x-intercepts happen when y=0.
Just like the y-intercepts happen when x=0.
So anyways we are asked to find the x-intercepts.
So set y=0 (set f(x)=0):
0=x^2+6x+5
0=ax^2+bx+c
Since a=1, all we have to do is find two numbers that multiply to be 5 and add up to be 6.
Those numbers are 5 and 1 because 5(1)=5 and 5+1=6.
So the factored form of x^2+6x+5 is (x+5)(x+1).
The equation we have is:
0=(x+5)(x+1).
This means we have x+5=0 or x+1=0.
We need to solve both equations.
x+5=0
Subtract 5 on both sides:
x=-5
x+1=0
Subtract 1 on both sides:
x=-1
So the x-intercepts are at (-5,0) and (-1,0).
OR
Some people just say at -5 and -1.
