Answer:
an =7+4(n-1)
Step-by-step explanation:
an =a1+ d(n-1) is the equation for an arithmetic sequence
When n=4 an =19
19 =a1 + d(4-1)
19 =a1 + d(3)
When n =6 an =27
27 = a1 +d*(6-1)
27 = a1 +d*5
Now we have 2 equations and 2 unknowns
19 =a1 + d(3)
27 = a1 +d*5
Subtract them to eliminate a1
27 = a1 +d*5
-19 =a1 + d(3)
-----------------------
8 = 2d
Divide by 2
8/2 = 2d/2
4 =d
The common difference is 4
Now we need to find a1
27 = a1 +d*5
27 = a1 + (4) *5
27 = a1+ 20
Subtract 20 from each side
27-20 =a1 +20-20
7 =a1
The initial term is 7
an = a1+ d(n-1)
an =7+4(n-1)
Answer:
See the attached
Step-by-step explanation:
When in doubt, draw a diagram.
The orthocenter of this acute triangle will be within its bounds. That should tell you right away that the y-coordinate of it will not be 8, but must be between 2 and 6.
The line perpendicular to BC through A must have a y-intercept greater than the y-coordinate of A, so cannot be 5. Whatever it is, the y-coordinate of the orthocenter will be less, so again, your answer fails the reasonableness test.
The perpendicular line to BC through A is ...
... y = (-1/2)(x -2) +6 = -x/2 +7 . . . . . . looks like you had a sign error in (-1/2)(-2)
The intersection of that line and x=6 is ...
... y = -6/2 +7 = 4
The only one that is not rational is the square root of 12.
Answer:
35*35=1225
37*37=1369
so a^+1225=1369
a^2=144
answer is the first option
Step-by-step explanation: