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frez [133]
3 years ago
11

18=w over 2 Please help and explain!

Mathematics
2 answers:
Mademuasel [1]3 years ago
4 0
18 =w/2 is 9 because 9•2=18
dusya [7]3 years ago
3 0

W is the variable.So try figuring out what the variable (W) represent and the value
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Using the points [164,166]and[173,174] find the slope
Lana71 [14]

Answer:

8/9

Step-by-step explanation:

The equation to find a slope is y2-y1/x2-x1=m. (m is the slope)

174-166/173-164

8/9

So the slope is 8/9.

8 0
3 years ago
What is 2.13 times 0.197
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Answer:

0.41961

Step-by-step explanation:

Line the numbers up, multiply, move the decimal five times to the left.

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3 years ago
Which expression is equivalent to 3x – 5?
Dvinal [7]

Answer:

2x – 4 – 1 + x

Step-by-step explanation:

5 0
3 years ago
The equation of function h is h... PLEASE HELP MATH
Flura [38]

Answer:

Part A: the value of h(4) - m(16) is -4

Part B: The y-intercepts are 4 units apart

Part C: m(x) can not exceed h(x) for any value of x

Step-by-step explanation:

Let us use the table to find the function m(x)

There is a constant difference between each two consecutive values of x and also in y, then the table represents a linear function

The form of the linear function is m(x) = a x + b, where

  • a is the slope of the function
  • b is the y-intercept

The slope = Δm(x)/Δx

∵ At x = 8, m(x) = 2

∵ At x = 10, m(x) = 3

∴ The slope = \frac{3-2}{10-8}=\frac{1}{2}

∴ a = \frac{1}{2}

- Substitute it in the form of the function

∴ m(x) = \frac{1}{2} x + b

- To find b substitute x and m(x) in the function by (8 , 2)

∵ 2 = \frac{1}{2} (8) + b

∴ 2 = 4 + b

- Subtract 4 from both sides

∴ -2 = b

∴ m(x) = \frac{1}{2} x - 2

Now let us answer the questions

Part A:

∵ h(x) = \frac{1}{2} (x - 2)²

∴ h(4) = \frac{1}{2} (4 - 2)²

∴ h(4) = \frac{1}{2} (2)²

∴ h(4) =  \frac{1}{2}(4)

∴ h(4) = 2

∵ m(x) = \frac{1}{2} x - 2

∴ m(16) =  \frac{1}{2} (16) - 2

∴ m(16) = 8 - 2

∴ m(16) = 6

- Find now h(4) - m(16)

∵ h(4) - m(16) = 2 - 6

∴ h(4) - m(16) = -4

Part B:

The y-intercept is the value of h(x) at x = 0

∵ h(x) = \frac{1}{2} (x - 2)²

∵ x = 0

∴ h(0) = \frac{1}{2} (0 - 2)²

∴ h(0) =  \frac{1}{2} (-2)² =  

∴ h(0) = 2

∴ The y-intercept of h(x) is 2

∵ m(x) = \frac{1}{2} x - 2

∵ x = 0

∴ m(0) = \frac{1}{2} (0) - 2 = 0 - 2

∴ m(0) = -2

∴ The y-intercept of m(x) is -2

- Find the distance between y = 2 and y = -2

∴ The difference between the y-intercepts of the graphs = 2 - (-2)

∴ The difference between the y-intercepts of the graphs = 4

∴ The y-intercepts are 4 units apart

Part C:

The minimum/maximum point of a quadratic function f(x) = a(x - h) + k is point (h , k)

Compare this form with the form of h(x)

∵ h = 2 and k = 0

∴ The minimum point of the graph of h(x) is (2 , 0)

∵ k is the minimum value of f(x)

∴ 0 is the minimum value of h(x)

∴ The domain of h(x) is all real numbers

∴ The range of h(x) is h(x) ≥ 2

∵ m(8) = 2

∵ m(14) = 5

∵ h(8) = \frac{1}{2} (8 - 2)² = 18

∵ h(14) = \frac{1}{2} (14 - 2)² = 72

∴ h(x) is always > m(x)

∴ m(x) can not exceed h(x) for any value of x

<em>Look to the attached graph for more understand</em>

The blue graph represents h(x)

The green graph represents m(x)

The blue graph is above the green graph for all values of x, then there is no value of x make m(x) exceeds h(x)

7 0
3 years ago
1. Find the domain and range of the function<br> f(x)=√1-4x².
slamgirl [31]

f(x) =  \sqrt{1 - 4{ x}^{2} }

1 - 4x {}^{2}  \geqslant 0

-  \infty  \:  \:  \:  \:  \:  \:  \:  \:  - 0.5 \:  \:  \:  \:  \:  \:  \:  \:  \: 0.5 \:  \:  \:  \:  \:  \:  \: \:   \infty  \\   -  \:  \:  \:  \:  \:  \:  \:  \: \:  \:  \:  \:  \: \:0  \:  \: \:  \:  \:   +  \:  \:  \:  \:0 \:  \:  \:  \:  \:   -

domain \\ [ \: -0.5 \: , \: 0.5 \: ]

g(x) = 1 - 4x {}^{2}  \\ g'(x) =  - 8x \\ g'(x) = 0 \\ x = 0 \\ g(0) = 1 - 4(0) = 1 \\ maximum \:  = 1

range  \\ [ \: 0 \:  ,  \: 1 \: ]

5 0
2 years ago
Read 2 more answers
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