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xenn [34]
3 years ago
14

What is 1 4/10 + 2 2/10

Mathematics
1 answer:
telo118 [61]3 years ago
6 0
1+2=3. 4/10+2/10=6/10. 3+ 6/10=3 6/10
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Given z1 = 2 +StartRoot 3 EndRoot i and z2 = 1 – StartRoot 3 EndRoot i, what is the sum of z1 and z2?
Fofino [41]

Answer:

z1 + z2 = 3

Step-by-step explanation:

Since we are given z1 = 2 + √(3)i and z2 = 1 – √(3)i. The sum of z1 + z2 would be:

(2 + √(3)i) + (1 – √(3)i) = 2 + √(3)i + 1 – √(3)i = 2 + 1 + √(3)i – √(3)i = 3

Hence, z1 + z2 = 3.

8 0
3 years ago
Read 2 more answers
-8= 3-5(x+6) solving algebraicaily​
SOVA2 [1]

Let's solve your equation step by step

-8=3-5(x+6)

Step 1: simplify both sides of the equation

-8=3-5(x+6)

-8=3+(-5)(x)+(-5(6) (distribute)

-8=3+-5x+-30

-8=(-5x)+(3+-30) (combine like terms)

-8=-5x+-27

-8=-5x-27

Step 2: flip the equation

-5x-27=-8

Step 3: add 27 to both sides

-5x-27+27=-8+27

-5x=19

Step 4: Divide both sides by -5

-5x/-5 = 19/-5

Answer : x= -19/5

4 0
4 years ago
Read 2 more answers
Can you help me please?
Alisiya [41]

Answer:

The correct answer is : C

Step-by-step explanation:

7 0
3 years ago
What is the means-to-MAD ratio of the two data sets, expressed as a decimal to the nearest tenth?
Romashka [77]
To find the mean of a set, add up all of the data points and divide by the number of data points.
For the first set:
(14+18+21+15+17) ÷ 5 = 85 ÷ 5 = 17
For the second set:
(15+17+22+20+16) ÷ 5 = 90 ÷ 5 = 18

To find the MAD (mean absolute deviation) of a set, find the mean of the distances of each data point from the mean.
For the first set:
(3+1+4+2+0) ÷ 5 = 10 ÷ 5 = 2
For the second set:
(3+1+4+2+2) ÷ 5 = 12 ÷ 5 = 2.4

To find the means-to-MAD ratio of a set, divide its mean by its MAD.
For the first set:
17 ÷ 2 = 8.5
For the second set:
18 ÷ 2.4 = 7.5
3 0
3 years ago
What is the anwser to the problem
torisob [31]

8 ) 712

8 goes into 71 8 times; the product of 8 and 8 is 64.

Subtracting this 64 from 71, we get 7, to which we append 2: 8 ) 72.

8 divides evenly into 72: 9.

Thus, the desired quotient is 89.

6 0
3 years ago
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