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Answer:
Mobile are build in a specific platform such as Android, iOS ect and they use application such as apple store and have access to the system such as GPS and the camera. Mobile apps live and run on mobiles as on they are their own thing controlled by a developer on the other end
Explanation:
Answer:
The following code is written in java programming language:
//set if statement
if (((modelYear >= 1999) && (modelYear <= 2002) && (modelName == "Extravagant")) || ((modelYear >= 2004) && (modelYear <= 2007) && (modelName == "Guzzler")))
{
recalled = true; //initialized Boolean value
}
else //set else statement
{
recalled = false; ////initialized Boolean value
}
Explanation:
Here, we set the if statement and set condition, if the value of modelYear is greater than equal to 1999 and less that equal to 2002 and modelName is equal to "Extravagant" or the value of modelYear is greater than equal to 2004 and less than equal to 2007 and the model year is equal to "Guzzler", than "recalled" initialized to "true".
Otherwise "recalled" initialized to "true".
Answer:
Assuming this is Python, I would do something like the following:
Explanation:
hourWage= float(input ("What is your hourly wage?: "))
regularHours= float(input ("How many regular hours did you work this week?: "))
overtimeHours= float(input ("How many overtime hours did you have this week?: "))
overtimeWage= (1.5*hourWage)
totalWeeklyPay= (hourWage*regularHours)+(overtimeHours*overtimeWage)
print= ("Your total weekly pay is: " ,totalWeeklyPay)
I hope this works!
Answer:
- public static String bothStart(String text1, String text2){
- String s = "";
-
- if(text1.length() > text2.length()) {
- for (int i = 0; i < text2.length(); i++) {
- if (text1.charAt(i) == text2.charAt(i)) {
- s += text1.charAt(i);
- }else{
- break;
- }
- }
- return s;
- }else{
- for (int i = 0; i < text1.length(); i++) {
- if (text1.charAt(i) == text2.charAt(i)) {
- s += text1.charAt(i);
- }else{
- break;
- }
- }
- return s;
- }
- }
Explanation:
Let's start with creating a static method <em>bothStart()</em> with two String type parameters, <em>text1 </em>&<em> text2</em> (Line 1).
<em />
Create a String type variable, <em>s,</em> which will hold the value of the longest substring that both inputs start with the same character (Line 2).
There are two possible situation here: either <em>text1 </em>longer than<em> text2 </em>or vice versa. Hence, we need to create if-else statements to handle these two position conditions (Line 4 & Line 13).
If the length of<em> text1</em> is longer than <em>text2</em>, the for-loop should only traverse both of strings up to the length of the <em>text2 </em>(Line 5). Within the for-loop, we can use<em> charAt()</em> method to extract individual character from the<em> text1</em> & <em>text2 </em>and compare with each other (Line 15). If they are matched, the character should be joined with the string s (Line 16). If not, break the loop.
The program logic from (Line 14 - 20) is similar to the code segment above (Line 4 -12) except for-loop traverse up to the length of <em>text1 .</em>
<em />
At the end, return the s as output (Line 21).
