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hjlf
3 years ago
12

A mixture of pulverized fuel ash and Portland cement to be used for grouting should have a compression strength of more than 130

0 KN/m^2. The mixture will not be used unless experimental evidence indicates conclusively that the strength specification has been met. Suppose compressive strength for specimens of this mixture is normally distributed with \sigma =60. Let \mu denote the true average compressive strength.What are the appropriate null and alternative hypothesis?
Mathematics
1 answer:
nekit [7.7K]3 years ago
7 0

Answer:

The null hypothesis is: u >= 1300 KN/m^2

And the alternative hypothesis is:

u < 1300 KN/m^2.

Step-by-step explanation:

The null hypothesis describes hat there is no difference or assiciation between variables of a specific population or that it is a particular average value while the alternative hypothesis states otherwise.

In this case study, the null hypothesis is: u >= 1300 KN/m^2

And the alternative hypothesis is:

u < 1300 KN/m^2.

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I need three terms like -19m
andreyandreev [35.5K]

Answer:

Step-by-step explanation:

ok  :3    

3 0
3 years ago
4505 x 219 standard algorithm
Ymorist [56]

After throughfall calculating the multiplication 4505 x 219 in standard algorithm, we have come to find that product is 986595

<h3>What is standard algorithm?</h3>

In elementary math, a standard algorithm or method is a particular computation technique that is typically taught for resolving particular mathematical issues. In general, these techniques include exchanging, regrouping, long division, long multiplication using a standard notation, and standard formulas for average, area, and volume.

These techniques can vary somewhat by country and time, but they typically include these techniques. Similar techniques are also available for more complex functions like square roots, but they are no longer taught in general mathematics classes because calculators are more convenient.

4505 x 219 in standard algorithm is as follows:

⇒        4 5 0 5

         <u>×    2 1 9  </u>            

        4 0 5 4 5    

    +  4 5 0 5        

  +<u> 9 0 1 0         </u>

     9 8 6 5 9 5

Learn more about standard algorithm

brainly.com/question/28819571

#SPJ9

   

4 0
1 year ago
What is the value x in 8+6y=9
natali 33 [55]

Answer:

0.64285714285

Step-by-step explanation:

8 + 6 = 14

9/14 = 0.64285714285

0.64285714285 * 14 = 9

Please vote Brainliest (:



4 0
3 years ago
Please help! I've been working on this for a few days and I just don't understand, it's due in a few hours. Thank you.
never [62]

Answer:

Part A: α = arc tan (y/x) = tan⁻¹ (y/x)

Part B: quadrant II α = arc tan (- y/x) = arc (- tan (y/x)) = - tan⁻¹ (y/x) 180°>α>90°

            quadrant III α = arc tan (-y)/(-x) = arc tan (y/x) = tan⁻¹ (y/x) 270°>α>180°

            quadrant IV α = arc tan (- y/x) = arc (- tan (y/x)) = - tan⁻¹ (y/x) 360°>α>270°

Part C: quadrant II 180°>α>90°  α = tan⁻¹ (-6/1) = - tan⁻¹ 6 = 180° - 80.53° = 99.47°

Step-by-step explanation:

PART A:

In this case we will use trigonometric function tanα to calculate angle α:

tanα = y/x => α = arc tan (y/x) = tan⁻¹ (y/x)

This formula is use in general way and in first quadrant  90°>α>0°

Part B:

But in the other quadrants you must know to use unit circle to reduce angle from II, III and IV quadrant to the first quadrant.

If angle is in the quadrant II  180°>α>90° then

tanα = - tan (180°-α)

If angle is in the quadrant III  270°>α>180° then

tanα = tan (α-180°)

If angle is in the quadrant IV  360°>α>270° then

tanα =- tan (360°-α)

Part C:

vector w (x,y) = (-1,6) this vector lies in quadrant II      180°>α>90°

180°- α = tan⁻¹ (-6/1) = - tan⁻¹ 6 = 80.53°  => 180° - α = 80.53°

α = 180° - 80.53 = 99.47°

It's not easy to understand this, but it's not easy for me to explain.

God with you!!!

5 0
2 years ago
PLEASE HELP, ILL GIVE BRAINLIEST! SIMPLE MATHS.
dusya [7]
The answer is c i’m pretty sure
7 0
2 years ago
Read 2 more answers
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