Hello! The answer should be B: 6i
![\sqrt{6](https://tex.z-dn.net/?f=%20%5Csqrt%7B6)
. Since the square root is above a negative, an imaginary number would come out. Because of this, you can easily recognize that it would be B.
However, if you can't, you could use the calculator to check (ignoring the negatives), 6
![\sqrt{6](https://tex.z-dn.net/?f=%20%5Csqrt%7B6)
is equal to
![\sqrt{216}](https://tex.z-dn.net/?f=%20%5Csqrt%7B216%7D%20)
.
The final answer should be B.
1/2(2+a)=3a+4/3
first, you use the distributive property<span>
</span>then your problem changes to...
1 + 1/2a = 3a + 4/3
then you subtract 1/2a with 3a
1 = 2 1/2a +4/3
<span>
now you subtract 1 with 4/3
</span>
-1/3 = 2 1/2a
now you divide -1/3 with 2 1/2a
-2/15 = a
A = -2/15 is your answer. Hope this helps :)
Answer:
8jbggvvhj was born on a 5
See the attached image for the graph. Specifically figure 2 is the graph you want. You can leave the red points on the graph or decide to erase them (leave behind the blue line though).
To generate each of the red points, you'll plug in various x values to get corresponding y values.
For instance, plug in x = 0 and we get...
y = -|x-6| - 6
y = -|0-6| - 6
y = -|-6| - 6
y = -6 - 6
y = -12
So when x = 0, the y value is -12. The x and y value pair up to get (x,y) = (0,-12)
Another example: plug in x = 2
y = -|x-6| - 6
y = -|2-6| - 6
y = -|-4| - 6
y = -4 - 6
y = -10
So the point (2,-10) is on the graph
The idea is to generate as many points as possible so we get an idea of what this thing looks like.
Generate enough points, and you'll get what you see in Figure 1 (see attached image)
Then draw a line through all of the points. The more points you use, the more accurate the drawing. Doing that will generate the blue function curve you see in Figure 2 (also attached)
For a 95% confidence interval, the corresponding z-score is 1.96. Therefore the deviation will by 1.96*0.5 lbs = 0.98 lbs. Therefore, the confidence interval will be (5 - 0.98, 5 + 0.98), which is (4.02, 5.98). The weight range is from 4.02 lbs to 5.98 lbs.