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Naddik [55]
3 years ago
6

What is the sum of the geometric sequence 3, 15, 75, … if there are 7 terms? 39,062 58,593 195,312 292,968?

Mathematics
2 answers:
PIT_PIT [208]3 years ago
8 0

Answer:

7th term is 46,875

Step-by-step explanation:

The given geometric sequence is 3, 15, 75.....

Here the first term a1 = 3, common ratio (r) = 15/3 = 5

The nth term an = a1.r^(n-1)

To find the 7th term, plug in n = 7.

a7 = 3. (5)^(7 -1)

a7 = 3.5^6

a7 = 3*15625

a7 = 46,875

Hope this will helpful.

Thank you.

AlexFokin [52]3 years ago
7 0
So to figure out the next number in the sequence you multply the previous number by 5
the first 7 terms are
3, 15, 75, 375, 1875, 9375, and 46875
then ad those all up and you get 58,593
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3² • 9³ = [ ]<br>solve ​
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Answer:

3⁸ or 6561

Step-by-step explanation:

First, let's look at PEMDAS - Parentheses, Exponents, Multiplication/Division, Addition/Subtraction.

There are no parentheses, so let's solve the exponents.

3² • 9³

3² = 9

9³ = 729

Your expression is:

9 • 729

Now let's multiply.

= 6561

This number can also be expressed with exponents.

Since 9 = 3², 9³ = 3²⁽³⁾

Now your expression is:

3² • 3²⁽³⁾

First, solve the exponents by multiplying.

3² • 3⁶

When you multiply two expressions with exponents that have the same base (3), you add the exponents.

3² • 3⁶ = 3⁽²⁺⁶⁾ = 3⁸

3⁸ also equals  6561.

Your answer is 3⁸ or 6561.

Hope this helps!

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