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3 years ago

Can you write 3 1/3 as an improper fraction

Mathematics

2 answers:

Volgvan3 years ago

5 0

Answer:

10/3

Step-by-step explanation:

One trick I learned for writing improper fractions is multiply the whole number by the denominator to then add to the numerator. So in this case 3*3=9 and 9+1=10. So the improper fraction is 10/3

Anton [14]3 years ago

4 0

Answer: 10/3 is the answer here you go

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What equation represents the line that passes through points (1.-5) and (3 -17)?

zzz [600]

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We know that:

$f(1) = -5 \implies a\cdot(1)+b = -5 \implies a+b = -5$

and

$f(3) = -17 \implies a\cdot(3) +b = -17 \implies 3a+b = 17$

Observe that:

$3a+b = 2a+a+b = 2a+(a+b)$

So:

$2a+(a+b) =-17$

But we know that $a+b = -5$ , so:

$2a+(a+b) =-17$

$2a+(-5) = -17$

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Since:

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So the line is:

$f(x) = 1-6x$

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3 years ago

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kipiarov [429]

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Nataly [62]

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natta225 [31]

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