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ZanzabumX [31]
3 years ago
10

I'm new to the app. Stumped on all of these

Mathematics
1 answer:
nekit [7.7K]3 years ago
3 0
What are you stumped on?
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In a school survey, 40% of students voted for a pizza party over an ice cream party. If 60 students voted for a pizza party, how
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3 years ago
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Triangle X Y Z is shown. The length of X Z is 12, the length of Y Z is 11, and the length of Y X is 6.
LenaWriter [7]

Answer:

84 degrees

Step-by-step explanation:

Applying the Cosine Rule (Choice 2 is the correct one)  :-

12^2 = 11^2 + 6^2 - 2*11*6 cos Y

144 = 121 + 36 - 132 cos Y

cos Y = (121 + 36 - 144) / 132

cos Y = 0.09848

Y = 84.3 degrees

7 0
3 years ago
Read 2 more answers
Based on the scale drawing, what is the length, in feet, of the actual parking lot? On the drawing they have the width 12.8 cm a
aleksandrvk [35]

Answer:

The width of 48 feet is represented by 12.8cm; the length represented by 1cm is 48/12.8 = 15/4 = 3.75 feet.

The length on the drawing is 3.2cm, which is exactly 1/4 of the width of 12.8cm; therefore the length of the actual parking lot is 48/4 = 12 feet.

5 0
3 years ago
See the picture <br><br> Please help
Vikki [24]

Step-by-step explanation:

f(-5) goes through y=-9

So, f(-5) = -9

6 0
3 years ago
Find the value of the variable.
nalin [4]

Answer:

The variable, y is 11°

Step-by-step explanation:

The given parameters are;

in triangle ΔABC;          {}              in triangle ΔFGH;

Segment \overline {AB} = 14         {}               Segment \overline {FG} = 14

Segment \overline {BC} = 27         {}              Segment \overline {GH} = 19

Segment \overline {AC} = 19         {}               Segment \overline {FH} = 2·y + 5

∡A = 32°                       {}                ∡G = 32°

∡A = ∠BAC which is the angle formed by segments \overline {AB} = 14 and \overline {AC} = 19

Therefore, segment \overline {BC} = 27, is the segment opposite to ∡A = 32°

Similarly, ∡G = ∠FGH which is the angle formed by segments \overline {FG} = 14 and \overline {GH} = 19

Therefore, segment \overline {FH} = 2·y + 5, is the segment opposite to ∡A = 32° and triangle ΔABC ≅ ΔFGH by Side-Angle-Side congruency rule which gives;

\overline {FH} ≅ \overline {BC} by Congruent Parts of Congruent Triangles are Congruent (CPCTC)

∴ \overline {FH} = \overline {BC} = 27° y definition of congruency

\overline {FH} = 2·y + 5 = 27° by transitive property

∴ 2·y + 5 = 27°

2·y = 27° - 5° = 22°

y = 22°/2 = 11°

The variable, y = 11°

8 0
3 years ago
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