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Nataly [62]
3 years ago
11

In one basketball season, Susan threw the ball and it went in the basket 56 times. If 7/8 of the baskets Susan threw were worth

2 points each and the remaining baskets were worth 3 points each, how many total points did Susan make in the season?
Mathematics
1 answer:
Ket [755]3 years ago
6 0

Answer:

119

Step-by-step explanation:

Divide the number of baskets (56) by the denominator:

56 ÷ 8 = 7

Multiply by 7 to get the amount of 2 point baskets and multiply by 1 to get the amount of 3 point baskets. (they both add up to 56 baskets)

7 × 7 = 49

7 × 1 = 7

multiply the 49, 2 point baskets by 2 and the 7, 3 point baskets by 3 and add them together to get the total points.

49 × 2 = 98

7 × 3 = 21

98 + 21 = 119

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LenKa [72]

Given:

The given sets are:

Set a : 200, 104, 100, 160.

Set b: 270, 400, 483, 300, x.

Mean of set a: mean of set b= 3:8

To find:

The value of x.

Solution:

Formula for mean:

Mean=\dfrac{\text{Sum of observations}}{\text{Number of observation}}

The mean of set of a is:

Mean=\dfrac{200+104+100+160}{4}

Mean=\dfrac{564}{4}

Mean=141

The mean of set of b is:

Mean=\dfrac{270+400+483+300+x}{5}

Mean=\dfrac{1453+x}{5}

Mean=\dfrac{1453+x}{5}

It is given that,

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\dfrac{141}{\dfrac{1453+x}{5}}=\dfrac{3}{8}

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Isolate the variable x.

5640-4359
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Divide both sides by 3.

\dfrac{1281}{3}
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Answer:

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Step-by-step explanation:

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