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3 years ago

8

What is the difference between a function and not a function ALGEBRA

2 answers:

Schach [20]3 years ago

6 0

There are 3 main parts of a function no matter what : input "x" also known as the domain, then a "function" which changes each input into an unique output, f(x), the artist formally known as "y" the outputs creates a known set called "range"

Hope I helped :)

RideAnS [48]3 years ago

5 0

<span>A function is a relation between a set of inputs and a set outputs. They have to be related to each other...
For example
1, 2, 3, 4, 5
2, 4, 6, 8, 10
Those two are a function.
Hope this Helps!</span>

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Use the graph above. In what quadrant does POINT C lay in?

PSYCHO15rus [73]

Quadrant number 3
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3 years ago

Read 2 more answers

Solve 2x + 8 < 10 or 2x + 8 > 20.

jasenka [17]

Answer:

x=1 or x=9

Step-by-step explanation:

make x the subject of the formula by correcting the right terms and then divid both sides by 2

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3 years ago

Who Can Answer this first for Extra Points? ( Must be correct )

xxTIMURxx [149]

Answer:

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Step-by-step explanation:

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3 years ago

Find the value of each variable in the following parallelograms.

Stella [2.4K]

Answer:

x = 15

y = 7.5

Step-by-step explanation:

✔️Diagonals of a parallelogram bisect each other at 90°.

Therefore,

2x° + 60° + 90° = 180° (sum of triangle)

Solve for x

2x + 150 = 180

2x = 180 - 150

2x = 30

2x/2 = 30/2

x = 15

✔️2x = 4y (alternate angles/corresponding angles)

Plug in the value of x

2(15) = 4y

30 = 4y

30/4 = y

7.5 = y

y = 7.5

7 0

3 years ago

Are two lines parallel, perpendicular or neither 3x+7y=15 and 7x-3y=6

maw [93]

Answer:

The lines are perpendicular

Step-by-step explanation:

we know that

If two lines are parallel, then their slopes are equal

If two lines are perpendicular, then their slopes are opposite reciprocal (the product of their slopes is equal to -1)

we have

$3x+7y=15$ ----> equation A

isolate the variable y

$7y=-3x+15$

Divide by 7 both sides

$y=-\frac{3}{7}x+\frac{15}{7}$

The slope of the line A is $m_A=-\frac{3}{7}$

$7x-3y=6$ ----> equation B

isolate the variable y

$3y=7x-6$

Divide by 3 both sides

$y=\frac{7}{3}x-2$

The slope of the line B is $m_B=\frac{7}{3}$

Compare the slope of both lines

$m_A=-\frac{3}{7}$

$m_B=\frac{7}{3}$

so

$m_A \neq m_B$ ----> the lines are not parallel

Find the product of the slopes

$-\frac{3}{7}(\frac{7}{3})=-1$ ----> the lines are perpendicular

4 0

4 years ago