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Andrews [41]
3 years ago
12

A car park is full. 1/3 of the cars leave.60% of the cars are red. There are 174 red cars. How many cars are left in the car par

k?
Mathematics
2 answers:
juin [17]3 years ago
5 0

Answer:

290

Step-by-step explanation:

60% of ⅔X = 174

60/100 × 2/3 × X = 174

⅖X = 174

X = 435

⅔X = ⅔×435

290

290 cars are left in the parking,

145 cars left

DedPeter [7]3 years ago
5 0

Answer:

Correction the answer is 290.

Step-by-step explanation:

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2√72 + 5√242 what is the answer for this question please can u tell me the right answer​
Radda [10]

Answer:

67\sqrt{2}

Step-by-step explanation:

Assuming you require to simplify the expression.

Using the rule of radicals

\sqrt{a} × \sqrt{b} ⇔ \sqrt{ab}

Simplifying the radicals

\sqrt{72} = \sqrt{36(2)} = \sqrt{36} × \sqrt{2} = 6\sqrt{2}

\sqrt{242} = \sqrt{121(2)} = \sqrt{121} × \sqrt{2} = 11\sqrt{2}

Then

2\sqrt{72} + 5\sqrt{242}

= 2(6\sqrt{2} ) + 5(11\sqrt{2} )

= 12\sqrt{2} + 55\sqrt{2}

= 67\sqrt{2}

6 0
3 years ago
A room has the area of 60 square meters and perimeter of 32 meters .What are the length and width of the room?
ad-work [718]
I am sorry but i don't no
4 0
3 years ago
Find an equation in standard form for the hyperbola with vertices at (0, ±9) and foci at (0, ±11)
Katen [24]

Answer:

\frac{y^{2} }{81} -\frac{x^{2} }{40} }=1 is standard equation of hyperbola with vertices at (0, ±9) and foci at (0, ±11).

Step-by-step explanation:

We have given the vertices at (0, ±9) and foci at (0, ±11).

Let (0,±a)  = (0,±9) and (0,±c)  = (0,±11)

The standard equation of parabola is:

\frac{y^{2} }{a^{2} } -\frac{x^{2} }{b^{2} }=1

From statement, a  = 9

c² = a²+b²

(11)²  = (9)²+b²

121-81  = b²

40  = b²

Putting the value of a² and b² in standard equation of parabola, we have

\frac{y^{2} }{81} -\frac{x^{2} }{40} }=1 which is the answer.

3 0
3 years ago
I need help to find the slope of the line the answers are <br> A: 4<br> B:-1/4<br> C:-4<br> D:1/4
dolphi86 [110]

Answer:

-1/4

Step-by-step explanation:

Take two points on the line

(-4,-1) and (0,-2)

Using the slope formula

m = (y2-y1)/(x2-x1)

   = ( -2 - -1)/( 0 - -4)

    = (-2+1)/ ( 0+4)

    -1/4

3 0
3 years ago
Mo bisects lmn m lmn 6x-28 m lmo x+34. find m
garri49 [273]
LMO+NMO = LMN,
x+34 + NMO = 6x-28
But, MO bisects LMN, so LMO=NMO
x+34 + x+34 = 6x-28
2x+68 = 6x-28
4x = 96
x = 24
That would makem it
24 + 34 =58 T NMO = 6(24)-28
58 + nmo = 144 - 28 = 119
116- 58 = 58
8 0
3 years ago
Read 2 more answers
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