Answer:
is standard equation of hyperbola with vertices at (0, ±9) and foci at (0, ±11).
Step-by-step explanation:
We have given the vertices at (0, ±9) and foci at (0, ±11).
Let (0,±a) = (0,±9) and (0,±c) = (0,±11)
The standard equation of parabola is:

From statement, a = 9
c² = a²+b²
(11)² = (9)²+b²
121-81 = b²
40 = b²
Putting the value of a² and b² in standard equation of parabola, we have
which is the answer.
Answer:
-1/4
Step-by-step explanation:
Take two points on the line
(-4,-1) and (0,-2)
Using the slope formula
m = (y2-y1)/(x2-x1)
= ( -2 - -1)/( 0 - -4)
= (-2+1)/ ( 0+4)
-1/4
LMO+NMO = LMN,
x+34 + NMO = 6x-28
But, MO bisects LMN, so LMO=NMO
x+34 + x+34 = 6x-28
2x+68 = 6x-28
4x = 96
x = 24
That would makem it
24 + 34 =58 T NMO = 6(24)-28
58 + nmo = 144 - 28 = 119
116- 58 = 58