Answer:
Q₂ = (9.83 × 10⁻⁹) C = +9.83 nC
Explanation:
The force of attraction/repulsion between the two charges is equal to the force of gravity on the charge 2.
The force of gravity on the charge two = mg
= 6.5 μg × 9.8 m/s² = (6.37 × 10⁻⁵) N
Since the gravity force is directed downwards, the force on charge 2 due to charge 1 has to be directed upwards, hence it is a force of repulsion.
The magnitude of the force between the two charges is given according to the Coulomb's law.
F = kQ₁Q₂/r²
k = Coulomb's constant = (9.0 × 10⁹) Nm²/C²
Q₁ = 45 nC = (45 × 10⁻⁹) C
Q₂ = ?
r = 25 cm = 0.25 m
F = (6.37 × 10⁻⁵) N
(6.37 × 10⁻⁵) = [(9.0 × 10⁹) × (45 × 10⁻⁹) × Q₂] ÷ 0.25²
Q₂ = 0.00000000983 C = (9.83 × 10⁻⁹) C = 9.83 nC
Hope this Helps!!!
