Answer:
7.08 m/s²
Explanation:
Given:
v₀ = 20.0 m/s
v = 105 m/s
t = 12.0 s
Find: a
v = at + v₀
105 m/s = a (12.0 s) + 20.0 m/s
a = 7.08 m/s²
Answer:
Explanation:
a. The source of centripetal force on the car is (3) the static friction force.
b. ac = v²/R = (20²)/50 = 8 m/s²
c. Fc = m(ac) = 1500(8) = 12 kN
d. μ = Fc/N = Fc/mg = 12000 / 1500(9.8) = 0.8163... ≈ 0.82
Answer:
A_resulting = 0.2 m
Explanation:
Let's analyze the impact of the pulse with the pole, this is a fixed obstacle that does not move therefore by the law of action and reluctant, the force that the pole applies on the rope is of equal magnitude to the force of the rope on the pole (pulse), but opposite directional, so the reflected pulse reverses its direction and sense.
With this information we analyze a point on the string where the incident pulse is and each reflected with an amplitude A = 0.1 m, the resulting is
A_res = 2A
A_resultant = 2 .01
A_resulting = 0.2 m
Answer:
Explanation:
The forces exerted by each mass is best understood in terms of their momentum.
Momentum is a sort of compelling force or impulse. It is given as:
Momentum = mass x velocity
Let us consider the momentum of the balls;
Substance C;
Mass = 1kg
Velocity = 5m/s
Momentum of C = 1 x 5 = 5kgm/s
Substance D:
Mass = 100kg
Velocity = 5m/s
Momentum of D = 100kg x 5m/s = 500kgm/s
Body D has a higher momentum compared to Body C. This suggests that body D will exert a higher force than C when they collide.
The higher the momentum, the more the force of impact it has.
If the rod is in rotational equilibrium, then the net torques acting on it is zero:
∑ τ = 0
Let's give the system a counterclockwise orientation, so that forces that would cause the rod to rotate counterclockwise act in the positive direction. Compute the magnitudes of each torque:
• at the left end,
τ = + (50 N) (2.0 m) = 100 N•m
• at the right end,
τ = - (200 N) (5.0 m) = - 1000 N•m
• at a point a distance d to the right of the pivot point,
τ = + (300 N) d
Then
∑ τ = 100 N•m - 1000 N•m + (300 N) d = 0
⇒ (300 N) d = 1100 N•m
⇒ d ≈ 3.7 m
