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3 years ago

Frank count by twos to 20. Elsie count by one to 10. Who will say more number? Explain

Mathematics

2 answers:

rosijanka [135]3 years ago

7 0

Frank and Elsie would say an equal amount of numbers because 2 goes into 20 ten times and 1 goes into 10 ten times.

Katyanochek1 [597]3 years ago

3 0

They will say equal because 1 goes into 10 ten times bc 1x10=10 and 2 goes into 20 10 times bc 2x10=20

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(w- 4/9) (-2/3) = -4/5 Solve for w

Kaylis [27]

exact form:

w= 74/45

decimal form:

w= 1.64

mixed number:

w= 1 29/45

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3 years ago

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W contains the best franchises of 2015 according to Entrepreneur. If W= {Hampton Hotels, Anytime Fitness, Subway, Jack in the Bo

weeeeeb [17]

Answer:

Proper Subsets = 1023

Step-by-step explanation:

Given $W= \{Hampton\ Hotels, Anytime\ Fitness, Subway, Jack\ in\ the\ Box, Supercuts, \\Jimmy\ Johns, Servpro, Denny's, Pizza\ Hut, 7-Eleven\}$

Required

Determine the proper subsets

Proper Subset (P) is calculated using;

$P = 2^n - 1$

Where

$n = number\ of\ elements$

In this case;

$n = 10$

So:

$P = 2^n - 1$

$P = 2^{10} - 1$

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Hence;

Proper Subsets = 1023

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3 years ago

Solve the system of inequalities 1-12y<:3y+1; 2-6y>4+4y

ICE Princess25 [194]

For 1 - 12y < 3y+1; y > 15

For 2 - 6y > 4 + 4y; y < -0.2

The given inequalities are:

1 - 12y < 3y + 1

2 - 6y > 4 + 4y

For 1 - 12y < 3y + 1:

1 - 12y < 3y + 1

Collect like terms

-12y - 3y < 1 - 1

-15y < 0

Multiply both sides by -1

-1(-15y) > 0(-y)

15y > 0

Divide both sides by 15

y > 0/15

y > 15

For 2 - 6y > 4 + 4y

Collect like terms

-6y - 4y > 4 - 2

-10y > 2

Multiply both sides by -1

-1(-10y) < 2(-1)

10y < -2

y < -2/10

y < -0.2

Learn more here: brainly.com/question/11316045

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3 years ago

Please help! Correct answer only, please! Consider the following information matrices for the price of clothing at a clothing st

ololo11 [35]

Answer: b) Large blue t-shirt & Medium RC jeans

Step-by-step explanation:

The subscript numbers attached to the matrix letter represents the:

ROW, COLUMN

$A=\left[\begin{array}{ccc}a_{1,1}&a_{1, 2}&a_{1, 3}\\a_{2,1}&a_{2, 2}&a_{2, 3}\\a_{3,1}&a_{3, 2}&a_{3, 3}\end{array}\right] \qquad B=\left[\begin{array}{ccc}a_{1,1}&b_{1, 2}&b_{1, 3}\\b_{2,1}&b_{2, 2}&b_{2, 3}\\b_{3,1}&b_{3, 2}&b_{3, 3}\end{array}\right]\\$

A₁,₃ = 1st row, 3rd column

1st row is Blue, 3rd column is Large

B₃,₂ = 3rd row, 2nd column

3rd row is RC jeans, 2nd column is Medium

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8 0

3 years ago

Please help me 40 points!!

MissTica

For f composite g, plug g into f
f(g)=6x^2+3
-3. -3
-3=6x^2
—. ——
6. 6
-3/6=x^2
square root of -3/6=x
then plug that number into
g composite f
f(f)=6(square root of /3/6)

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3 years ago

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