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irga5000 [103]
3 years ago
14

W3* 5 = 15. then 15 + 5 equals what number? 3 05 08 15​

Mathematics
1 answer:
Anastaziya [24]3 years ago
6 0

Answer:

Hello

ur answer is

15+5= 20

Step-by-step explanation:

thanks hope it helps

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One side of a triangle is 13 feet shorter than the second side. The third side is 1 feet longer than the second side. The perime
Papessa [141]

Answer:

let second side be x

then first side = x-13

third side= x+1

now

perimeter of triangle = 45

x-13+x+x+1=45

3x=57

x=19

first side = x-13= 19-13=6

third side= x+1=19+1=20

Step-by-step explanation:

4 0
3 years ago
How to do this question
RoseWind [281]
Idek hun I don’t see anything
3 0
3 years ago
Please help me solve for x =
Sladkaya [172]

Answer:

x = 13

Step-by-step explanation:

Given that Δ NML and Δ PST are similar right triangles, we can set up the following proportional statement to establish their relationship:

\frac{ML}{NM} = \frac{ST}{PS}

\frac{8}{10} = \frac{x - 1}{x + 2}

Cross multiply:

8(x + 2) = 10 (x - 1)

8x + 16 = 10x - 10

Subtract 8x from both sides:

8x - 8x + 16 = 10x - 8x - 10

16 = 2x - 10

Add 10 to both sides:

16 + 10 = 2x - 10 + 10

26 = 2x

Divide both sides by 2:

\frac{26}{2} = \frac{2x}{2}

13 = x

Verify whether x = 13 is the correct value:

\frac{ML}{NM} = \frac{ST}{PS}

\frac{8}{10} = \frac{x - 1}{x + 2}

\frac{8/2}{10/2} = \frac{4}{5}

\frac{x -1}{x+2} =  \frac{13 - 1}{13 + 2} = \frac{12}{15} = \frac{12 / 3}{15 /3} = \frac{4}{5}

This shows the proportional relationship between \frac{ML}{NM} = \frac{ST}{PS}, and that ΔNML and ΔPST are indeed similar right triangles.

Therefore, the correct answer is x = 13.

4 0
3 years ago
Given: are diameters m∠3 = <br> A) 39 <br> B) 78<br> C) 102
Blizzard [7]
I just did this a few seconds ago and the correct answer is 78. The check above the number is green which means its correct. 
8 0
3 years ago
Read 2 more answers
Given that log3(z - 1) - logz z = 1+ 3 log3 y, express z in terms of y.
fgiga [73]

Answer:

  z = 1 + 9y³

Step-by-step explanation:

It looks like you have ...

  \log_3{(z-1)}-\log_z{(z)}=1+3\log_3{(y)}\\\\\log_3{(z-1)}-1=1+\log_3{(y^3)}\\\\\log_3{(z-1)}=2+\log_3{(y^3)}\qquad\text{add 1}\\\\z-1=(3^2)(y^3)\qquad\text{take antilog}\\\\\boxed{z=1+9y^3}\qquad\text{add 1}

6 0
4 years ago
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