Answer:
40 mm
Explanation:
=Proper Length of rod = 2.05 m
Speed of rod = 6.01×10⁷ m/s
Length contraction
Final Length will be 2.01 m
So length that is contracted is 2.05-2.01 = 0.04 m
The length is contracted by 40 mm.
Answer:
5.08m
Explanation:
Charge on an electron=
Number of electrons=2
Mass of electron=
Weight of electron=mg
Where g=Acceleration due to gravity=9.8
Using the formula
Weight of an electron=N
Force between two electrons =Weight of an electron
We know that
Electrostatic force =
Where Charge
r=Distance between two charges
Using the formula
Hence, the distance between two electrons=5.08m
Answer:
a) Ffr = -0.18 N
b) a= -1.64 m/s2
c) t = 9.2 s
d) x = 68.7 m.
e) W= -12.4 J
f) Pavg = -1.35 W
g) Pinst = -0.72 W
Explanation:
a)
- While the puck slides across ice, the only force acting in the horizontal direction, is the force of kinetic friction.
- This force is the horizontal component of the contact force, and opposes to the relative movement between the puck and the ice surface, causing it to slow down until it finally comes to a complete stop.
- So, this force can be written as follows, indicating with the (-) that opposes to the movement of the object.
where μk is the kinetic friction coefficient, and Fn is the normal force.
- Since the puck is not accelerated in the vertical direction, and there are only two forces acting on it vertically (the normal force Fn, upward, and the weight Fg, downward), we conclude that both must be equal and opposite each other:
- We can replace (2) in (1), and substituting μk by its value, to find the value of the kinetic friction force, as follows:
b)
- According Newton's 2nd Law, the net force acting on the object is equal to its mass times the acceleration.
- In this case, this net force is the friction force which we have already found in a).
- Since mass is an scalar, the acceleration must have the same direction as the force, i.e., points to the left.
- We can write the expression for a as follows:
c)
- Applying the definition of acceleration, choosing t₀ =0, and that the puck comes to rest, so vf=0, we can write the following equation:
- Replacing by the values of v₀ = 15 m/s, and a = -1.64 m/s2, we can solve for t, as follows:
d)
- From (1), (2), and (3) we can conclude that the friction force is constant, which it means that the acceleration is constant too.
- So, we can use the following kinematic equation in order to find the displacement before coming to rest:
- Since the puck comes to a stop, vf =0.
- Replacing in (7) the values of v₀ = 15 m/s, and a= -1.64 m/s2, we can solve for the displacement Δx, as follows:
e)
- The total work done by the friction force on the object , can be obtained in several ways.
- One of them is just applying the work-energy theorem, that says that the net work done on the object is equal to the change in the kinetic energy of the same object.
- Since the final kinetic energy is zero (the object stops), the total work done by friction (which is the only force that does work, because the weight and the normal force are perpendicular to the displacement) can be written as follows:
f)
- By definition, the average power is the rate of change of the energy delivered to an object (in J) with respect to time.
- If we choose t₀=0, replacing (9) as ΔE, and (6) as Δt, and we can write the following equation:
g)
- The instantaneous power can be deducted from (10) as W= F*Δx, so we can write P= F*(Δx/Δt) = F*v (dot product)
- Since F is constant, the instantaneous power when v=4.0 m/s, can be written as follows:
Answer:
the density of gold is 19.3 g/cc
In the mass spectrum of pentane, the presence of a peak with m/z = 15 is most likely due to the detection of A) methyl radical cation that has been lost from the spectrum.
<h3>Mass Spectrum</h3>
The m/z ratios of any ions contained in a sample displayed against their intensities that forms a mass spectrum.
The height of the peaks in any kind of mass spectrum denotes the relative abundance of the various components in the sample, and each peak in a mass spectrum displays a component that a distinct m/z is in the sample.
<h3>How do mass spectra function?</h3>
Only when a molecule has been transformed into a gas-phase ion can a mass spectrometer calculate the mass of the molecule.
In order to do this, it gives molecules an electrical charge and transforms the flow of electrically charged ions that results into a proportional electrical current that a data system can subsequently read.
<h3>Give an example of the mass spectral range.</h3>
Whenever any molecules are ionized in an ionization box, many different kinds of ions have been created.
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Complete Question
In the mass spectrum of pentane, the presence of a peak with m/z = 15 is most likely to the detection of: _________-
A) Methyl Radical
B) Ethyl Radical
C) Propyl Radical
D) Butyl Radical