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UkoKoshka [18]
2 years ago
10

An ocean wave is an example of what type of wave​

Physics
1 answer:
Tanzania [10]2 years ago
7 0

Answer:

It is called a surface wave (rayleigh wave) that transmits its energy with the wind blowing onto its surface.Hope this helps

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The dimension line is connected to the part being measured by _______________. A. Hidden lines B. Extension lines C. Visible lin
kondaur [170]
B: Extension Lines! You could have just searched this up on google
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According to Newton's law of cooling, the rate at which an object's temperature changes is directly proportional to the differen
Kryger [21]

Answer:

dT(t)/dt = k[T5 - T(t)]

Explanation:

Since T(t) represents the temperature of the object and T5 represents the temperature of the surroundings, according to Newton's law of cooling, the rate at which an object's temperature changes is directly proportional to the difference in temperature between the object and the surrounding medium, that is dT(t)/dt ∝ T5 - T(t)

Introducing the constant of proportionality

dT(t)/dt = k[T5 - T(t)]

which is the desired differential equation

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2 years ago
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When reaching a boundary between two media (1 and 2), an incident ray is partially reflected and partially refracted. The ray is
lukranit [14]

Answer:

The angle of incidence when the reflected ray is perpendicular to the incident ray = 45°

Explanation:

According to Snell's Law,

n₁ sin θ₁ = n₂ sin θ₂

When the angle between the incident ray and reflected ray is 90°, the angle of incidence is θ₁ and the angle of reflection, θ₂ = 90° - θ₁ and the index of refraction in the Snell's Law for both media would be the same, n₁ = n₂ = n

n sin θ₁ = n sin (90° - θ₁)

Note that from trigonometric relations,

Sin (90° - θ₁) = cos θ₁

n sin θ₁ = n cos θ₁

(sin θ₁)/(cos θ₁) = 1

tan θ₁ = 1

θ₁ = arctan 1 = 45°

Hope this Helps!!!

7 0
3 years ago
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a car is going around a roundabout.explain why we say that it is accelerating even if it is moving at a constant speed.
kiruha [24]

Because 'acceleration' does NOT mean 'speeding up'. 
It means ANY change in motion ... speeding up, slowing down,
or changing DIRECTION.

When traveling a roundabout, or any curved path, the direction
is constantly changing even if the speed is constant, so there is
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4 0
3 years ago
A guitar string with a length of 80.0 cm is plucked. The speed of a wave in the string is 400 m/sec. Calculate the frequency of
Sholpan [36]

Answer:

The first harmonic is: 250Hz, second harmonic 500Hz, third harmonic 750Hz.

Explanation:

Use the frequency f, speed v, and wavelentgh L relationship:

v = f\cdot L\implies f = \frac{v}{L}

We are given the speed v=400 m/s. The base wavelength on a string of length 80cm is twice the length of the string (a "half wave" along the full length of the string), so:

f = \frac{400\frac{m}{s}}{2\cdot0.8 m}= 250\frac{1}{s}=250 Hz

The fundamental frequency (first harmonic) is 250 Hz

The second harmonic is produced by one full wave across the string (adding one node in the middle), so L=80cm in this case, therefore the second harmonic frequency is: f2 = 2*250=500Hz

the third harmonic add another node (and a half wave) to the pattern and the wavelength will be 2/3 of 80cm, so f3=3*250Hz = 750Hz


8 0
2 years ago
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