The rms speed can be calculated using the following rule:
rms = sqrt ((3RT) / (M)) where:
R is the gas constant = 8.314 J/mol-K
T is the temperature = 31.5 + 273 = 304.5 degrees kelvin
M is the molar mass = 2*14 = 28 grams = 0.028 kg
Substitute with the givens to get the rms speed as follows:
rms speed = sqrt [(3*8.314*304.5) / (0.028)] = 520.811 m/sec
Answer:
1850 N
Explanation:
The formula for friction force between the load and plane is given as ;
F= μ*N
N = mg cos θ
To find θ, which is the angle the inclined plane makes with the ground at the height of 1.5 m
Sin θ = 1.5/4.5
Sin θ = 0.3333
Sin⁻{0.3333} = 19.50°
θ = 19.50°
Finding N , where m= 500 N , and g= 9.81
N = mg cos θ
N= 500 * 9.81 * cos 19.50°
N= 4624 N
Coefficient of kinetic friction is calculated as;
μ=F/W
μ = 200/500 = 0.4
The magnitude of kinetic friction is given as;
Fk= μ * N
Fk = 0.4 * 4624
Fk= 1850 N
