Given : - Square ABCD with side 3. E and F as midpoints.
To find : - area of EBFD
Solution : - We have, area of square ABCD = 3 x 3 = 9 units.
Thus, (ar)EBFD = ar ABCD - ar DAE - arDCF
arDAE = 1/2 x base x height
=1/2 x 1.5 x 3 ( AE is 1/2 of AB = 1.5, DA is altitude)
= 2.25
arDFC = 1/2 x base x height
= 1/2 x 1.5 x 3 (FC is 1/2 of BC, DC is altitude)
= 2.25
Thus, (ar) EBFD = arABCD - arDAE - arDCF
= 9 - 2.25 - 2.25
= 4.5 units.
Thus, area of quad EBFD is 4.5 units.
Answer:
w = 13
Step-by-step explanation:
Using the method of cross- multiplying
• = ⇒ ad = bc, thus
42(w + 11) = 28(w + 23) ← distribute parenthesis on both sides
42w + 462 = 28w + 644 ( subtract 28w from both sides )
14w + 462 = 644 ( subtract 462 from both sides )
14w = 182 ( divide both sides by 14 )
w = 13
Distribution method
(2x+6)(2x-6)
=4x^2-12x+12x-36
=4x^2-36
Answer:
EF=BC (by CPCT) if both Triangle are ~