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2 years ago

How do I solve the problem k-10/2=-29

Mathematics

1 answer:

Ilia_Sergeevich [38]2 years ago

6 0

K is -24. 10/2:5 so -24-5=-29

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suppose that $17,000 is deposited for six years at 5% APR. Calculate the interest earned if interest is compounded quartly . Rou

Lapatulllka [165]

$\bf ~~~~~~ \textit{Compound Interest Earned Amount}
\\\\
A=P\left(1+\frac{r}{n}\right)^{nt}
\quad 
\begin{cases}
A=\textit{accumulated amount}\\
P=\textit{original amount deposited}\to &\$17000\\
r=rate\to 5\%\to \frac{5}{100}\to &0.05\\
n=
\begin{array}{llll}
\textit{times it compounds per year}\\
\textit{quarterly, thus four}
\end{array}\to &4\\
t=years\to &6
\end{cases}
\\\\\\
A=17000\left(1+\frac{0.05}{4}\right)^{4\cdot 6}\implies A=17000(1.0125)^{24}$

the earned interest will then be A - P, namely A - 17000.

5 0

3 years ago

Yesterday Priya successfully made 12 free throws. Today she made 150% as many. How many successful free throws and Priya make to

TiliK225 [7]

12 • 1.5 = 18

1.5 = 150%

Your answer is, 18 free throws

4 0

2 years ago

Rewrite the fraction as a decimal. <br> {57}{5}= 5 57

Inessa [10]

Answer: 11.4

Step-by-step explanation: In the fraction 57/5, 57 is the numerator and 5 is the denominator, the fraction bar means "divided by". Therefore, the fraction 57/5 is same as "57 divided by 5" or "57 ÷ 5".

When we calculated 57 divided by 5, we found that 57/5 in decimal form is:57 ÷ 5 = 11.4 Therefore, the decimal form of 57/5 is 11.4

Hope I helped <3

8 0

1 year ago

Need help ASAP !!!<br><br><img src="https://tex.z-dn.net/?f=%20%5Csqrt%7B26548%20%5Ctimes%2026548%7D%20" id="TexFormula1" title=

miskamm [114]

Answer:

√{26548×26548}=√26548²=±26548

6 0

2 years ago

Read 2 more answers

A genetics experiment involves a population of fruit flies consisting of 1 male named Bart and 3 females named Charlene, Diana,

kenny6666 [7]

Answer:

(b) $\frac{1}{2}$

Step-by-step explanation:

1 male named Bart (b)

3 females named Charlene(c), Diana(d), and Erin(e).

Since there is replacement, the possible samples are:

bb, bc, be, bd, cb, cc, cd, ce, db, dc, dd, de, eb, ec, ed, and ee.

Total Number of pairs = 16

Event of picking 2 males:bb

Event of 1 male:bc,cb,bd,db,be,eb

Event of picking 0 males:

cc, cd, ce, dc, dd, de, ec, ed, and ee.

$\begin{equation*} \begin{matrix}Proportion of males & Probability \\0 & 9/16 \\1 & 6/16 \\2 & 1/16 \end{matrix} \end{equation*}$

b. The mean of the sampling distribution

$\mu = (\frac{9}{16} X0 ) +(\frac{6}{16} X 1)+(\frac{1}{16} X 2) = \frac{8}{16} = \frac{1}{2}$

c. No; the proportion of males is $\frac{1}{4}$ while the mean is $\frac{1}{2}$ .

B. No, the sample mean is not equal to the population proportion of males. These values are not always equal, because proportion is an unbiased estimator.

7 0

2 years ago