What is 7/8 times 4 1/6

rosijanka [135]

$\bf \qquad \textit{Quad identities}\\\\
sin(4\theta )=
\begin{cases}
8sin(\theta )cos^3(\theta )-4sin(\theta )cos(\theta )\\
4sin(\theta )cos(\theta )-8sin^3(\theta )cos(\theta )
\end{cases}
\\\\\\
cos(4\theta)=8cos^4(\theta )-8cos^2(\theta )+1\\\\
-------------------------------\\\\
9cos(4x)\implies 9[8cos^4(x)-8cos^2(x)+1]
\\\\\\
72cos^4(x)-72cos^2(x)+9$

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as far as the previous one on the 2tan(3x)

$\bf tan(2\theta)=\cfrac{2tan(\theta)}{1-tan^2(\theta)}\qquad tan({{ \alpha}} + {{ \beta}}) = \cfrac{tan({{ \alpha}})+ tan({{ \beta}})}{1- tan({{ \alpha}})tan({{ \beta}})}\\\\
-------------------------------\\\\$

$\bf 2tan(3x)\implies 2tan(2x+x)\implies 2\left[ \cfrac{tan(2x)+tan(x)}{1-tan(2x)tan(x)}\right]
\\\\\\
2\left[ \cfrac{\frac{2tan(x)}{1-tan^2(x)}+tan(x)}{1-\frac{2tan(x)}{1-tan^2(x)}tan(x)}\right]\implies 2\left[ \cfrac{\frac{2tan(x)+tan(x)-tan^3(x)}{1-tan^2(x)}}{\frac{1-tan(x)-2tan^3(x)}{1-tan^2(x)}} \right]
\\\\\\$

$\bf 2\left[ \cfrac{2tan(x)+tan(x)-tan^3(x)}{1-tan^2(x)}\cdot \cfrac{1-tan^2(x)}{1-tan(x)-2tan^3(x)} \right]
\\\\\\
2\left[ \cfrac{3tan(x)-tan^3(x)}{1-tan^2(x)-2tan^3(x)} \right]\implies \cfrac{6tan(x)-2tan^3(x)}{1-tan^2(x)-2tan^3(x)}$

4 0

2 years ago

Please help me iam so confused , help please?

Nina [5.8K]

Answer:

x= 45 degrees

Step-by-step explanation:

the top angle is a eight angle which is equal to 90 all triangles are 180 degrees both bottom angles are equal and 180 minus the 90 degree from the right angle is 90 degrees you divide that by 2 and you have your answer

4 0

3 years ago

Read 2 more answers

X/3-15=-2 solve for x

Otrada [13]

Answer:

x = 45

Step-by-step explanation:

Rearrange the equation by subtracting what is to the right of the equal sign from both sides of the equation :

x/3-(15)=0

Step 1 : Simplify

$\frac{x}{3}$

Equation at the end of step 1 :

$\frac{x}{3}$ - 15 = 0

Step 2 :

Rewriting the whole as an Equivalent Fraction :

Subtracting a whole from a fraction

Rewrite the whole as a fraction using 3 as the denominator :

$15=\frac{15}{1} =\frac{15*3}{3}$

Equivalent fraction : The fraction thus generated looks different but has the same value as the whole

Common denominator : The equivalent fraction and the other fraction involved in the calculation share the same denominator

Adding fractions that have a common denominator :

Adding up the two equivalent fractions

Add the two equivalent fractions which now have a common denominator

Combine the numerators together, put the sum or difference over the common denominator then reduce to lowest terms if possible:

$\frac{x-(15*3)}{3} =\frac{x-45}{3}$

Equation at the end of step 2 :

$\frac{x-45}{3} =0$

Step 3 :

When a fraction equals zero :

Where a fraction equals zero, its numerator, the part which is above the fraction line, must equal zero.

Now,to get rid of the denominator, Tiger multiplys both sides of the equation by the denominator.

Here's how:

$\frac{x-45}{3}*3=0*3$

Now, on the left hand side, the 3 cancels out the denominator, while, on the right hand side, zero times anything is still zero.

The equation now takes the shape :

x-45 = 0

Solving a Single Variable Equation :

Solve : x-45 = 0

Add 45 to both sides of the equation :

x = 45

One solution was found :

x = 45

3 0

3 years ago

Five times the larger number is 11 more than three time the smaller number. Also three times the smaller is 16 less four times t

alisha [4.7K]

Let the larger number be w and the smaller number be k;
5w-11=3k
3k+16=4w
Reorganizing the equations;
5w-3k=11
4w-3k=16
Subtracting equation 2 from equation 1:
w=-5
Replacing value of w in equation 1;
5(-5)-11=3k
-25-11=3k
3k=-36
k=-12
The numbers are -5 and -12

3 0

2 years ago

Use properties of logarithms to condense the logarithmic expression. write the expression as a single logarithm whose coefficien

Kitty [74]

$\log\left( \frac{4x + 5}{x} \right) = \log(4 + \frac{5}{x})$

4 0

2 years ago

Read 2 more answers