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3 years ago

You can buy 20 fluid ounces of shampoo for $4.40 or 24 fluid ounces for $4.80. Which is the better buy? Explain.

2 answers:

8 0

Ok, so you put $4.40 over 20 ounces which will get you $ 0.22 per ounce
You do the same for the other one.

4.80 over 24 ounces which is $ 0.20 per ounce
So the better price would be 24 fluid ounces of shampoo for $ 4.80

lidiya [134]3 years ago

6 0

First you have to do 440 / 20, which is 22 cents per bottle
Next you have to do 480 / 24, which is 20 cents per bottle
20 < 22, so the 24 ounces of shampoo is the correct answer.

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The formula to calculate the area of a circle from its circumference is: A =c2/4π

densk [106]

Answer:

(if its a true or false question) True

Step-by-step explanation:

We know-

Area of a circle =

A=(π)r2

Circumference of a circle =

C=2(π)r

Where pi is a constant and r is the radius of the circle.

Using these two formulas we can express A in terms of C as follows:

c2=[2(π)r]2

⇒ c2=4[(π)2]r2 ⇒ c2=4(π)[(π)r2]

As (π)r2=A ⇒c2=4(π)A

Therefore:

A=c2/4(π)

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3 years ago

The proof that UX ≅ SV is shown. Given: △STU an equilateral triangle ∠TXU ≅ ∠TVS Prove: UX ≅ SV What is the missing statement in

iren2701 [21]

Triangle STU is congruent to triangle UTX is the missing step. AAS (angle-angle-side) is a method of proving 2 triangles congruent, and using the already proved information, you can find the triangles that are congruent by AAS.

6 0

3 years ago

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14. Given: 5x + 4y = 24, x + 7y= 11; Prove: y= 1 Statements reasons

Semenov [28]

Answer:

Step-by-step explanation:

We can use the process of elimination as

5x + 4y = 24

5(x + 7y = 11) —> 5x + 35y = 55

5x + 4y = 24

-(5x + 35y = 55)

—————————

-31y = -31

-31y/-31 = -31/-31

y=1

4 0

3 years ago

Math question

strojnjashka [21]

Answer:

The candle has a radius of 8 centimeters and 16 centimeters and uses an amount of approximately 1206.372 square centimeters.

Step-by-step explanation:

The volume ( $V$ ), in cubic centimeters, and surface area ( $A_{s}$ ), in square centimeters, formulas for the candle are described below:

$V = \pi\cdot r^{2}\cdot h$ (1)

$A_{s} = 2\pi\cdot r^{2} + 2\pi\cdot r \cdot h$ (2)

Where:

$r$ - Radius, in centimeters.

$h$ - Height, in centimeters.

By (1) we have an expression of the height in terms of the volume and the radius of the candle:

$h = \frac{V}{\pi\cdot r^{2}}$

By substitution in (2) we get the following formula:

$A_{s} = 2\pi \cdot r^{2} + 2\pi\cdot r\cdot \left(\frac{V}{\pi\cdot r^{2}} \right)$

$A_{s} = 2\pi \cdot r^{2} +\frac{2\cdot V}{r}$

Then, we derive the formulas for the First and Second Derivative Tests:

First Derivative Test

$4\pi\cdot r -\frac{2\cdot V}{r^{2}} = 0$

$4\pi\cdot r^{3} - 2\cdot V = 0$

$2\pi\cdot r^{3} = V$

$r = \sqrt[3]{\frac{V}{2\pi} }$

There is just one result, since volume is a positive variable.

Second Derivative Test

$A_{s}'' = 4\pi + \frac{4\cdot V}{r^{3}}$

If $\left(r = \sqrt[3]{\frac{V}{2\pi}}\right)$ :

$A_{s} = 4\pi + \frac{4\cdot V}{\frac{V}{2\pi} }$

$A_{s} = 12\pi$ (which means that the critical value leads to a minimum)

If we know that $V = 3217\,cm^{3}$ , then the dimensions for the minimum amount of plastic are:

$r = \sqrt[3]{\frac{V}{2\pi} }$

$r = \sqrt[3]{\frac{3217\,cm^{3}}{2\pi}}$

$r = 8\,cm$

$h = \frac{V}{\pi\cdot r^{2}}$

$h = \frac{3217\,cm^{3}}{\pi\cdot (8\,cm)^{2}}$

$h = 16\,cm$

And the amount of plastic needed to cover the outside of the candle for packaging is:

$A_{s} = 2\pi\cdot r^{2} + 2\pi\cdot r \cdot h$

$A_{s} = 2\pi\cdot (8\,cm)^{2} + 2\pi\cdot (8\,cm)\cdot (16\,cm)$

$A_{s} \approx 1206.372\,cm^{2}$

The candle has a radius of 8 centimeters and 16 centimeters and uses an amount of approximately 1206.372 square centimeters.

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3 years ago

I need some help with this two.

andrey2020 [161]

Answer: a = 2168 miles

b= $3360.40

Hope this helps!

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2 years ago

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