An electron starts from rest 3.00 cm from the center of a uniformly charged sphere of radius 2.00 cm. if the sphere carries a to
tal charge of 1.00 10 9 c, how fast will the electron be moving when it reaches the surface of the sphere?
1 answer:
Answer:
velocity = 7.26 * 10^6 m/sec
Explanation:
The rule that is used to solve this problem is shown in the attached image.
The variables are as follows:
k = 8.99 * 10^9 Nm^2 / C^2
e is the electron charge = -1.6 * 10^-19 C
q is the charge given = 1 * 10^-9 C
m is the mass of the electron = 9.11 * 10^-31
r1 is the radius of starting point = 3 cm = 0.03 m
r2 is the radius of the sphere = 2 cm = 0.02 m
Substitute with the givens in the equation to get the value of the velocity
Hope this helps :)
velocity = 7.26 * 10^6 m/sec
Explanation:
The rule that is used to solve this problem is shown in the attached image.
The variables are as follows:
k = 8.99 * 10^9 Nm^2 / C^2
e is the electron charge = -1.6 * 10^-19 C
q is the charge given = 1 * 10^-9 C
m is the mass of the electron = 9.11 * 10^-31
r1 is the radius of starting point = 3 cm = 0.03 m
r2 is the radius of the sphere = 2 cm = 0.02 m
Substitute with the givens in the equation to get the value of the velocity
Hope this helps :)
You might be interested in