An electron starts from rest 3.00 cm from the center of a uniformly charged sphere of radius 2.00 cm. if the sphere carries a to
tal charge of 1.00 10 9 c, how fast will the electron be moving when it reaches the surface of the sphere?
1 answer:
Answer:
velocity = 7.26 * 10^6 m/sec
Explanation:
The rule that is used to solve this problem is shown in the attached image.
The variables are as follows:
k = 8.99 * 10^9 Nm^2 / C^2
e is the electron charge = -1.6 * 10^-19 C
q is the charge given = 1 * 10^-9 C
m is the mass of the electron = 9.11 * 10^-31
r1 is the radius of starting point = 3 cm = 0.03 m
r2 is the radius of the sphere = 2 cm = 0.02 m
Substitute with the givens in the equation to get the value of the velocity
Hope this helps :)
velocity = 7.26 * 10^6 m/sec
Explanation:
The rule that is used to solve this problem is shown in the attached image.
The variables are as follows:
k = 8.99 * 10^9 Nm^2 / C^2
e is the electron charge = -1.6 * 10^-19 C
q is the charge given = 1 * 10^-9 C
m is the mass of the electron = 9.11 * 10^-31
r1 is the radius of starting point = 3 cm = 0.03 m
r2 is the radius of the sphere = 2 cm = 0.02 m
Substitute with the givens in the equation to get the value of the velocity
Hope this helps :)
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Answer:
<h2>The answer is 2.5 m/s²</h2>Explanation:
The acceleration of an object given it's velocity and time taken acting on it can be found by using the formula
From the question
time = 4 s
velocity = 10 m/s
So we have
We have the final answer as
<h3>2.5 m/s²</h3>Hope this helps you
Explanation:
Given that,
Electric field, E = 7900 V/m
Magnetic field,
(a) Let v is the velocity of a beam of electrons that goes undeflected when moving perpendicular to an electric and magnetic fields. The magnitude of electric force and the magnetic force balance each other as :
(b) Let r is the radius of the electron orbit. The radius of the motion of electron is given by :
Hence, this is the required solution.