Answer:
Periodic
Explanation:
A periodic (or repetitive) wave has continuously repeating pattern with characteristics such as amplitude, wavelength and frequency. In a periodic wave, a series of pulses that are evenly timed would be created. In other words, the wave pattern in a periodic wave repeats at regular intervals.
An example of a periodic wave is the sound from the strings of a violin.`
The Earth's orbital period change is A: It would increase by 0.15 years
Using Kepler's third law which states that the square of the orbital period of the planet is directly proportional to the cube of its distance from the sun.
So, T² ∝ R³
T'²/T² = R'³/R³ where
- T = orbital period at R = 1 year
- R = initial axis length = 1 AU
- T' = orbital period at R'
- R' = final axis length = 1.1 AU.
So, making T' subject of the formula, we have
T' = [√(R'/R)³]T
T' = [√(1.1 AU/1 AU)³] × 1 year
T' = [√(1.1)³] × 1 year
T' = √1.331 × 1 year
T' = 1.15 × 1 year
T' = 1.15 years.
So, the change in the Earth's orbital period ΔT = T' - T
= 1.15 years - 1 year
= 0.15 years
Since this is positive, the orbital period <u>increases</u> by 0.15 years.
So, the Earth's orbital period change is A: It would increase by 0.15 years
Learn more about Kepler's third law here:
brainly.com/question/16546004
D. 8.12×10^7g - 6.20×10^6g
Answer:
speed of flow of blood in the blocked portion of the vessel is 9.18 vo
Explanation:
given data
diameter of the vessel = 67.0 %
to find out
what is its speed v expressed as a multiple of vo
solution
we know here that Plaque decreases diameter of the vessel by 67%
s here diameter in the blocked portion = 33% of diameter in unblocked portion so
we will apply here Continuity equation that is express as
Ao×Vo = A1×V1 ...................1
here Ao is Cross-sectional area of the cylindrical blood vessel that is =
and do is Diameter of the cylindrical blood vessel and vo is Speed of flow of blood in the blood vessel
and d1 is diameter of the vessel in the blocked portion of the vessel that is = 0.33 do and A1 is cross section area of the vessel in the blocked portion that is = and v1 is Speed of flow of blood in the blocked portion of the vessel
so now we put value in equation 1 we get
Ao×Vo = A1×V1
× vo = × v1
do²×vo = d1²×v1
do²×vo = d1²×v1
do²×vo = (0.33 do)²×v1
solve it we get
v1 = 9.18 vo
so speed of flow of blood in the blocked portion of the vessel is 9.18 vo