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pantera1 [17]
3 years ago
14

WHY IS SATURN ONE OF THE COLDEST PLANETS IN OUR SOLAR SYSTEM

Physics
1 answer:
Usimov [2.4K]3 years ago
4 0
What are the answer choices?
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the difference between any two successive numbers always seems to be _ more than the preceding difference
erma4kov [3.2K]

Here's li^{}nk to the answer:

cutt^{}.ly/4Rq^{}tIvk

6 0
2 years ago
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a cyclist coasting down a 5.0 ◦ incline at a constant speed of 6.0 km/h because of air resistance. If the total mass of the bicy
Dvinal [7]

Answer:

F_{net}= 85.41\ N

Explanation:

mass of the bicycle + cyclist = 50 kg

constant speed = 6 km/h

a cyclist coasting down a 5.0° incline

the downward velocity is constant, so net acceleration must be zero

the air drag must be equal to gravitational force downward along the ramp

F_a = mg sin \theta  

now for upward motion

F_{net} = mg sin \theta + air\ drag

F_{net} = mg sin \theta + mg sin \theta

F_{net} = 2 mg sin \theta

F_{net} = 2\times 50 \times 9.8 sin 5^0

F_{net}= 85.41\ N

3 0
3 years ago
Sound waves can travel through which mediums?
aksik [14]

Answer:

B. Solids, liquids, and gases.

Explanation:

I have no explanation.

5 0
3 years ago
Uma wants to recreate the discovery of superconductivity. Which describes the materials needed?
zaharov [31]

Answer:

B)a tool to drop temperatures, mercury, an electric current, and a tool to measure resistance

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3 years ago
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A sphere of radius R contains charge Q spread uniformly throughout its volume. Find an expression for the electrostatic energy c
tensa zangetsu [6.8K]

Answer:

E = \frac{3kQ^2}{5R}

Explanation:

Let the sphere is uniformly charge to radius "r" and due to this charged sphere the electric potential on its surface is given as

V = \frac{kq}{r}

now we can say that

q = \frac{Q}{\frac{4}{3}\pi R^3} (\frac{4}{3}\pi r^3)

q = \frac{Qr^3}{R^3}

now electric potential is given as

V = \frac{k\frac{Qr^3}{R^3}}{r}

V = \frac{kQr^2}{R^3}

now work done to bring a small charge from infinite to the surface of this sphere is given as

dW = V dq

dW = \frac{kQr^2}{R^3} dq

here we know that

dq = \frac{3Qr^2dr}{R^3}

now the total energy of the sphere is given as

E = \int dW

E = \int_0^R  \frac{kQr^2}{R^3} (\frac{3Qr^2dr}{R^3})

E = \frac{3kQ^2}{R^6} (\frac{R^5}{5} - 0)

E = \frac{3kQ^2}{5R}

7 0
3 years ago
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