<h3>
Answer:</h3>
20% calcium and 80% Bromine
<h3>
Explanation:</h3>
- The percentage composition of an element in a compound is given by dividing the mass of the element in the compound by the relative formula mass of the compound and expressing it as a percentage.
- % Composition = (mass of element in 1 mole of compound /relative formula mass of the compound) 100%
Our compound is CaBr₂
Formula mass = 200 g
Relative atomic mass of Ca = 40.078
Relative atomic mass of Br = 79.904
Therefore;
% composition of Ca = (40.078/200) 100%
= 20.039
= 20 %
% composition of Br = (79.904×2)/200) 100%
= 79.904 %
= 80%
Therefore; the approximate % composition by mass of CaBr₂ is 20% calcium and 80% Bromine
The question is incomplete. Complete question is:
<span>All of the following containers have the same volume and temperature, which container has the most molecules
container 1-25.0 atm
container 2-50.0 atm
container 3- 12.5 atm
container 4- 1.00 atm
...........................................................................................................................
From, ideal gas equation, we know that PV = nRT
Thus, number of moles of gas depends on pressure, volume and temperature. Since, volume and temperature are held constant. number of moles of molecules will depends only on pressure of gas.
From above equation is can be seen that n </span>α P. Thus higher the pressure, more will be the molecules.
∴ In present case, container 2 will have <span>most molecules, as it has maximum pressure. </span>
Answer: Pink R-groups contain primarily C and H, which have approximately equal electronegativities and lack O; most green R-groups also contain a highlyelectronegative O atom.Green R-groups contain primarily C and H, which have approximately equal electronegativities and lack O; most pink R-groups contain a highlyelectronegative O atom
Explanation: I've been researching it for a while now
- NH₃: Hydrogen bonds;
- CCl₄: London Dispersion Forces; (a.k.a. Induced dipole)
- HCl: Dipole-dipole Interactions.
<h3>Explanation</h3>
Relative strength of intermolecular forces in small molecules:
Hydrogen bonds > Dipole-dipole interactions > London DIspersion Forces.
It takes two conditions for molecules in a substance to form <em>hydrogen bonds</em>.
- They shall contain at least one of the three bonds: H-F, O-H, or N-H.
- They shall contain at least one lone pair of electrons.
NH₃ contains N-H bonds. The central nitrogen atom in an NH₃ molecule has one lone pair of electrons. NH₃ meets both conditions; it is capable of forming hydrogen bonds.
CCl₄ molecules are nonpolar. The molecule has a tetrahedral geometry. Dipole from the polar C-Cl bonds cancel out due to symmetry. The molecule is nonpolar overall. As a result, only London Dispersion Force is possible between CCl₄ molecules.
HCl molecules are polar. The H-Cl bond is fairly polar. The HCl molecule is asymmetric, such that the dipole won't cancel out. The molecule is overall polar. Both dipole-dipole interactions and London Dispersion Force are possible between HCl molecules. However, dipole-dipole interactions are most predominant among the two.
Answer:
The system gains 126100 J
Explanation:
The heat can be calculated by the equation:
Q = nxCxΔT, where Q is the heat, C is the heat capacity,n is the number of moles and ΔT is the variation of temperature (final - initial). The number of moles is the mass divided by the molar mass, so:
n = 250/4 = 62.5 mol.
The system must be in thermal equilibrium with the surroundings, so if the temperature of the surroundings decreased 97 K, the temperature of the system increased by 97 K, so ΔT = 97 K
Q = 62.5x20.8x97
Q = 126100 J