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3 years ago

Which two equations would be most appropriately solved by using the zero product property? Select each correct answer.

Mathematics

1 answer:

ss7ja [257]3 years ago

8 0

Answer:

1) (x + 4)(x - ½) = 0

4x² + 16x = 0

2) 0.25x² + 0.8x - 8 = 0

3x² - 4x = 15

Step-by-step explanation:

1) (x + 4)(x - ½) = 0

x = -4, ½

4x² + 16x = 0

4x(x + 4) = 0

x = 0, -4

2) (x - 6)(x + 9) = 0

x = 6, -9

(x - 1)² = 4

(x - 1)² - (2)² = 0

(x - 1 - 2)(x - 1 + 2) = 0

(x - 3)(x + 1) = 0

x = 3, -1

These two are easier to solve using product = 0 property, while the other two would be easier using the quadratic formula

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3 years ago

What is the value of (4-2)^3-3X4

Mazyrski [523]

<h2>Answer:</h2>

$3 x^{4}-8=0$

<h2>Given: </h2>

$(4-2)^{3}-3 x^{4}$

<h2>Step-by-step explanation:</h2>

In this problem, we need to find the value of the given expression for which we need to simplify the given expression.

$\Rightarrow(4-2)^{3}-3 x^{4}=0$

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3 years ago

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If the temperature after 4.4 degree drop was -2.5 degrees Celsius what was the temperature at noon

Lostsunrise [7]

Answer:

1.9°C

Step-by-step explanation:

Let X be the temperature at noon and -2.5°C be the current temperature after the drop.

-We calculate temperature at noon as:

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Hence, the temperature at noon was 1.9°C

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