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alexira [117]
3 years ago
5

I need help with all of it

Mathematics
1 answer:
kakasveta [241]3 years ago
5 0
When you bring something up or move something down, you have to multiply the exponent by -1. So in this case, you are bringing up the exponent. Multiply 5 by -1 and your answer should be x^5/1.
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In a 30-60-90 triangle, the length of the long leg is 8. Find the length of the hypotenuse.
fiasKO [112]

Answer:

Step-by-step explanation:

In a 30-60-90 triangle, the ratio of the lengths of the angles' opposite sides are <em>1-√3-2</em>.

If the long leg is 8, then the short one is 8/√3, or <em>8√3/3</em>.

Therefore, the hypotenuse, which is <em>double the short leg</em>, is 16√3/3.

5 0
3 years ago
Which of the following could be the perimeter of a rectangle with an area of 16 square inches?
emmasim [6.3K]

Answer:

16 inches

Step-by-step explanation:

6 0
3 years ago
Read 2 more answers
Point E is between points D and F. If DE = x − 2, EF = 6x + 4, and DF = 8x − 2, find x
Arlecino [84]
DE + EF = DF

x - 2 + 6x + 4 = 8x - 2
7x + 2 = 8x - 2
2 + 2 = 8x - 7x
4 = x <===
3 0
3 years ago
A) how many ways are there to choose 10 players to take the field?
Kruka [31]

A. C(13, 10) = 13! = 13·12·11 = 13 · 2 · 11 = 286.C(13, 10) = 13! = 13·12·11 = 13 · 2 · 11 = 286.

B. P(13,10)= 13! =13! =13·12·11·10·9·8·7·6·5·4. (13−10)! 3!

C. f there is exactly one woman chosen, this is possible in C(10, 9)C(3, 1) =

10! 3!

9!1! 1!2! 10! 3!

8!2! 2!1! 10! 3!

7!3! 3!0!

= 10 · 3 = 30 ways; two women chosen — in C(10,8)C(3,2) =

= 45·3 = 135 ways; three women chosen — in C(10, 7)C(3, 3) =

= 10·9·8 ·1 = 120 ways. Altogether there are 30+135+120 = 285 1·2·3

<span>possible choices.</span><span> 
</span>

  


5 0
4 years ago
Lila added three-fourths of a bag of soil to her garden. Her neighbor
Drupady [299]

Answer:

lila added 1/12 more than fiona

Step-by-step explanation:

find GCF (12), multiply amounts added accordingly

lila added 9/12 (multiply 3/4 by 3)

fiona added 2/3 (multiply 2/3 by 4)

4 0
3 years ago
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