Answer:
a) Binomial distribution B(n=12,p=0.01)
b) P=0.007
c) P=0.999924
d) P=0.366
Step-by-step explanation:
a) The distribution of cracked eggs per dozen should be a binomial distribution B(12,0.01), as it can model 12 independent events.
b) To calculate the probability of having a carton of dozen eggs with more than one cracked egg, we will first calculate the probabilities of having zero or one cracked egg.

Then,

c) In this case, the distribution is B(1200,0.01)

d) In this case, the distribution is B(100,0.01)
We can calculate this probability as the probability of having 0 cracked eggs in a batch of 100 eggs.

Ha. That looks alot like i-ready. (i-ready sucks butt.)
But the horror that is i-ready aside, your answer is the third one : The proportion of grandparents that feel safe entering their account information online is 0.32.
32% converted to a decimal is 0.32, and 68% converted to a decimal is 0.68. That would mean that the proportion for grandparents that feel safe doing so is 0.32, and the number of grandparents that don't feel safe doing so is 0.68.
I believe the answer is 2 :) .
Answer:
5 * 5 * 5 * 5
Step-by-step explanation:
Use the rules of Indices.
5⁶⁻²
= 5⁴