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Svetlanka [38]
2 years ago
14

What is the pH of pure water? 2.0 5.0 7.0 12.0

Chemistry
1 answer:
stealth61 [152]2 years ago
7 0
7.0 this is the correct answer
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Juan Carlos placed 35 grams of ke into a dry, 200-gram container. The top of the container was attached tightly. When the ice wa
lianna [129]
Correct answer is D
8 0
3 years ago
भारत के एक ही राज्य में लगातार सबसे लंबे समय तक
IgorLugansk [536]

Answer:

C

Explanation:

6 0
3 years ago
So I saw this question: If 28.0 grams of Pb(NO3)2 react with 18.0 grams of NaI, what mass of PbI2 can be produced? Pb(NO3)2 + Na
Nataly_w [17]

mass of PbI₂ = 27.6606 g

<h3>Further explanation</h3>

Given

Pb(NO₃)₂ + NaI → PbI₂ + NaNO₃

28.0 grams of Pb(NO₃)₂ react with 18.0 grams of NaI

Required

mass of PbI₂

Solution

Balanced equation

Pb(NO₃)₂ + 2NaI → PbI₂ + 2NaNO₃

The principle of a balanced reaction is the number of atoms in the reactants = the number of atoms in the product

mol Pb(NO₃)₂ :

= 28 : 331,2 g/mol

= 0.0845

mol NaI :

= 18 : 149,89 g/mol

= 0.12

Limiting reactant : mol : coefficient

Pb(NO₃)₂ : 0.0845 : 1 = 0.0845

NaI : 0.12 : 2 = 0.06

NaI limiting reactant (smaller ratio)

mol PbI₂ based on NaI

= 1/2 x 0.12 = 0.06

Mass PbI₂ :

= 0.06 x 461,01 g/mol

= 27.6606 g

4 0
3 years ago
The mole fraction of NaCl in an
posledela

The weight/weight percent(%w/w) of NaCl in  solution : 33.03%

<h3>Further explanation</h3>

Given

Mole fraction of NaCl : 0.132

Required

The weight/weight percent of NaCl

Solution

1 mol solution : 0.132 mol NaCl + 0.868 mol H₂O

mass NaCl :

\tt 0.132\times 58.44 g/mol=7.714~g

mass H₂O :

\tt 0.868\times 18.016~g/mol=15.64~g

Total mass = 7.714 + 15.64 = 23.354 g

\tt \%NaCl=\dfrac{7.714}{23.354}\times 100\%=33.03\%

6 0
3 years ago
Part D<br> Explain how your model is different from the model in the picture.
Ipatiy [6.2K]

Answer:

I am explain you in image

8 0
3 years ago
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