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Evgen [1.6K]
3 years ago
7

Give the measurement following sig fig rules for tools. Do not forget the unit after your number measurement.​

Chemistry
1 answer:
In-s [12.5K]3 years ago
5 0

Answer:

Explanation:

You are not really helped by what is hold the liquid. Beakers and cylinders come on a lot of sizes. I hate to be crabby about things like that, but you really need to be aware that the question is slightly flawed (not your fault).

The beaker, you'd be like to get 1 sig digit. You have to be awfully careful about claiming more. So the and is 50 mL, but that mL is a guess and the 50 is not totally accurate, but what would you say the second digit is? 48 or 47? You don't really know. Maybe even 49.

The graduated cylinder is a little better. Read the bottom of the meniscus (the bottom of the 1/2 bubble). I think you can get 2 sig digs., so the answer is 36 mL. But everything also depends on what you have been told.

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3 years ago
Pls help asap!!!!
AVprozaik [17]

Answer: The pressure of the He is 2.97 atm

Explanation:

According to Dalton's law, the total pressure is the sum of individual pressures.

p_{total}=p_{N_2}+p_{O_2}+p_{He}.

Given : p_{total} =total pressure of gases = 6.50 atm

p_{N_2} = partial pressure of Nitrogen = 1.23 atm

p_{O_2} = partial pressure of oxygen = 2.3 atm

p_{He} = partial pressure of Helium = ?

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3 0
3 years ago
Balance the following equation Sa+ F2---> SF6
deff fn [24]

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8 0
3 years ago
3) What is the weight of the ethyl alcohol that exactly fills a
Leto [7]

Answer:

158g

Explanation:

To calculate the "weight" (mass) of ethyl alcohol, we have to use this formula:

- Density will have units of gmL when dealing with a liquid or units of gcm3 when dealing with a solid.

The mass has units of grams, g.

The volume will have units of mL or cm3

We are given the density and volume, both of which have good units so all we have to do is rearrange the equation to solve for the mass:

density×volume=massvolume×volume

Density×Volume = Mass

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Thus, ethyl alcohol weighs 158g.

3 0
3 years ago
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