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4 years ago

When an electric field is applied to a metallic crystal, the movement of electrons is?

1 answer:

4 0

When an electric field is applied to a metallic crystal, the movement of electrons is random. Metals form giant structures in which electrons in the outer shells of the metal atoms are free to move. Hope this answers the question. Have a nice day.

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Cual es el propósito de la línea escalonada gruesa de la tabla periódica

noname [10]

Separa los metales de los no metales. Agregame como amiga, saludos.

3 0

3 years ago

When you do a displacement reaction with iron and copper what is the orange metal called

laiz [17]

It is called rust and it forms when water soaks into the metal forming a chemical reaction.

5 0

3 years ago

Consider a mixture of air and gasoline vapor in a cylinder with a piston. The original volume is 40. cm3. If the combustion of t

maks197457 [2]

Answer:

The gases will expand until a volume of Vf= 10812 cm^3

Explanation:

Since the gas mixture is expanding at constant pressure

$W=\int\limits^{Vf}_{Vi} {P} \, dV =P(Vf-Vi)$

and therefore

$Vf=W/P+Vi$

knowing that 1 torr=133,32 Pa

$p=635 torr * 133,322 Pa/torr * 1m^{3}/10^{6}cm^{3}=0,08466 J/ cm^{3}$

therefore

$Vf=912 J/(0,08466 J/cm^{3}) +40cm^{3} =10812 cm^{3}$

8 0

3 years ago

A 30.0 L sample of nitrogen inside a rigid, metal container at 20.0 °C is placed inside an oven whose temperature is 50.0 °C. Th

Scorpion4ik [409]

Answer:

3.31 atm.

Explanation:

Gay-Lussac's law states that for a given mass and constant volume of an ideal gas, the pressure exerted on the sides of its container is directly proportional to its absolute temperature.

∵ P α T.

∴ P₁T₂ = P₂T₁.

P₁ = 3.00 atm, T₁ = 20.0 °C + 273.15 = 293.15 K.

P₂ = ??? atm, T₂ = 50.0 °C + 273.15 = 323.15 K.

∴ P₂ = (P₁T₂)/T₁ = (3.00 atm)( 323.15 K)/(293.15 K) = 3.307 atm ≅ 3.31 atm.

6 0

3 years ago

I need help with # 7

mihalych1998 [28]

They have the same number of valence electrons.

7 0

3 years ago