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sattari [20]
3 years ago
13

Formula to calculate Speed of election​

Chemistry
1 answer:
Kay [80]3 years ago
4 0

Answer:

Step 1: Identify the Equation of Interest · Step 2: Determine the Potential Difference Across the Field · Step 3: Solve for the Speed

Explanation:

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Of the element listed wich
Nesterboy [21]

The atomic radius trend on the Periodic Table is as follows:

- Atomic radius increases down a column (or group)

- Atomic radius decreases across rows (or periods) from left to right

Looking at my Periodic Table, calcium, chromium, cobalt and copper are in that order from left to right in the same period, which simplifies things significantly.

Since these elements are in the same period, and given that we know atomic radius decreases across periods from left to right, we can see that calcium has the largest atomic radius.

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C. kinetic energy to electrical energy.

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What mass of water must be added to 5g of nacl to make 5% mass persentage of the solution?
Vitek1552 [10]

Answer:-

95 grams

Explanation:-

Let the mass of water to be added be M

So total mass = 5 + M

So 5% of this solution has 5g of NaCl by mass.

∴ (M+5) x (5/100) = 5

M+5 = 5 x 100/5

M+5=100

M= 100-5

95

So amount of water to be added is 95 gram

8 0
3 years ago
One of the radioactive isotopes used in medical treatment or analysis is chromium-51. The half-life of chromium-51 is 28 days. H
Goryan [66]

Answer : The time required for decay is, 84 days.

Explanation :

Half-life of chromium-51 = 28 days

First we have to calculate the rate constant, we use the formula :

k=\frac{0.693}{t_{1/2}}

k=\frac{0.693}{28\text{ days}}

k=0.0248\text{ days}^{-1}

Now we have to calculate the time required for decay.

Expression for rate law for first order kinetics is given by:

t=\frac{2.303}{k}\log\frac{a}{a-x}

where,

k = rate constant

t = time taken by sample = ?

a = let initial activity of the sample = 100

a - x = amount left after decay process  = 12.5

Now put all the given values in above equation, we get

t=\frac{2.303}{0.0248}\log\frac{100}{12.5}

t=83.9\text{ days}\approx 84\text{ days}

Therefore, the time required for decay is, 84 days.

7 0
3 years ago
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