Question

How do you convert p(x) = -8x^2 - 64x to vertex form?

Answer 1

Answer:

$p(x)=-8(x+4)^2+128$

Step-by-step explanation:

Given, $p(x)=-8x^2-64x$

Take -8 factor common,

$p(x)=-8(x^2+8x)$

which can be written as

$p(x)=-8(x^2+2 \times 4x)$

Add and subtract by 16 inside bracket,

$p(x)=-8(x^2+2 \times 4x+16-16)$

$p(x)=-8((x^2+2 \times 4x+4^2)-16)$

$p(x)=-8((x+4)^2-16)$

$p(x)=-8(x+4)^2+8 \times 16$

$p(x)=-8(x+4)^2+128$