KD is congruent to AT as:
<h3>angles are of equal measure</h3><h3>sides KD and TA are equal</h3><h3>sides DT and KA are equal</h3>
The figure is kite as has two pairs of same sides.
<h3>They are constructed in a way of having same angle.</h3>
The initial statement is: QS = SU (1)
QR = TU (2)
We have to probe that: RS = ST
Take the expression (1): QS = SU
We multiply both sides by R (QS)R = (SU)R
But (QS)R = S(QR) Then: S(QR) = (SU)R (3)
From the expression (2): QR = TU. Then, substituting it in to expression (3):
S(TU) = (SU)R (4)
But S(TU) = (ST)U and (SU)R = (RS)U
Then, the expression (4) can be re-written as:
(ST)U = (RS)U
Eliminating U from both sides you have: (ST) = (RS) The proof is done.
Answer:
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