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liberstina [14]
3 years ago
9

Which set of sides will not make a triangle?

Computers and Technology
2 answers:
Lesechka [4]3 years ago
7 0

Answer:

b

Explanation:

stellarik [79]3 years ago
6 0

Answer:

The answer is B

Explanation:

12 cm, 7 cm, and 5 cm.

Add 5 + 7 and get 12

Sides added must be greater, not equal to.

You might be interested in
If one breakfast meal of banana lacatan, scrambled egg, plain rice, and hot milk contains 58 grams carbohydrate, 12 grams protei
enyata [817]

Answer:

Total amount of calories = 325

Explanation:

Given:

Amount of carbohydrate = 58 gram

Amount of protein = 12 gram

Amount of fat = 5 gram

Find:

Total amount of calories

Computation:

1 gram protein = 4 calories

1 gram carbohydrate = 4 calories

1 gram fat = 9 calories

Total amount of calories = (58)(4) + (12)(4) + (5)(9)

Total amount of calories = 232 +48 + 45

Total amount of calories = 325

5 0
3 years ago
Show the array that results from the following sequence of key insertions using a hashing system under the given conditions: 5,
sergejj [24]

Answer:

a) Linear probing is one of the hashing technique in which we insert values into the hash table indexes based on hash value.

Hash value of key can be calculated as :

H(key) = key % size ;

Here H(key) is the index where the value of key is stored in hash table.

----------

Given,

Keys to be inserted are : 5 , 205, 406,5205, 8205 ,307

and size of the array : 100.

First key to be inserted is : 5

So, H(5) = 5%100 = 5,

So, key 5 is inserted at 5th index of hash table.

-----

Next key to inserted is : 205

So, H(205) = 205%100 = 5 (here collision happens)

Recompute hash value as follows:

H(key) =(key+i) % size here i= 1,2,3...

So, H(205) =( 205+1)%100 = 206%100 = 6

So, key 205 is inserted in the 6th index of the hash table.

----------

Next Key to be inserted : 406

H(406) = 406%100 = 6(collision occurs)

H(406) =(406+1) %100 = 407%100 = 7

So, the value 406 is inserted in 7the index of the hash table.

-----------------

Next key : 5205

H(5205) = 5205%100 = 5(collision)

So, H(5205) = (5205+1)%100 = 6( again collision)

So, H(5205) = 5205+2)%100 = 7(again collision)

So, H(5205) = (5205+3)%100 = 8 ( no collision)

So, value 5205 is inserted at 8th index of the hash table.

-------------

Similarly 8205 is inserted at 9th index of the hash table because , we have collisions from 5th to 8th indexes.

-------------

Next key value is : 307

H(307) = 307%100 = 7(collision)

So, (307+3)%100 = 310%100 = 10(no collision)  

So, 307 is inserted at 10th index of the hash table.

So, hash table will look like this:

Key       index

5         5

205         6

406         7

5205 8

8205 9

307         10

b) Quadratic probing:

Quadratic probing is also similar to linear probing but the difference is in collision resolution. In linear probing in case of collision we use : H(key) = (key+i)%size but here we use H(key) =( key+i^2)%size.

Applying Quadratic probing on above keys:.

First key to be inserted : 5.

5 will go to index 5 of the hash table.

-------

Next key = 205 .

H(205) = 205%100 = 5(collision)

So. H(key)= (205+1^2)%100 = 6(no collision)

So, 205 is inserted into 6th index of the hash table.

--------

Next key to be inserted 406:

So, 406 %100 = 6 (collision)

(406+1^2)%100 = 7(no collision)

So, 406 is moved to 7th index of the hash table.

----------

Next key is : 5205

So, 5205%100 = 5 (collision)

So, (5205+1^2)%100 = 6 ( again collision)

So, (5205+2^2)%100 = 9 ( no collision)

So, 5205 inserted into 9th index of hash table.

-----------

Next key is 8205:

Here collision happens at 5the , 6the , 9th indexes,

So H(8205) = (8205+4^2)%100 = 8221%100 = 21

So, value 8205 is inserted in 21st index of hash table.

--------

Next value is 307.

Here there is collision at 7the index.

So, H(307) = (307+1^2)%100 = 308%100= 8.

So, 307 is inserted at 8the index of the hash table.

Key           Index

5                  5

205                  6

406                  7

5205                9

8205               21

307                   8

3 0
3 years ago
Create a base class named rectangle that contains lenght and width data members.
kumpel [21]

Answer:

class Rectangle:  

   

   def __init__(self, length, width):

       self.length = length

       self.width = width

       

   

   def area(self):

       area = self.length*self.width

       return area

   

   

class Box (Rectangle):

   

   def __init__(self, length, width, height):

       super().__init__(length, width)

       self.height = height

       

   def volume(self):

       volume = self.length * self.width * self.height

       return volume

   

   def area(self):

       area = 2*(self.length*self.width) + 2*(self.length*self.height) + 2*(self.width*self.height)

       return area

rec_1 = Rectangle(2,4)

box_1 = Box(2,2,6)

print(box_1.length)

print(box_1.area())

   

print(rec_1.length)

print(rec_1.area())

Explanation:

The programming language used is python.

class Rectangle

The class Rectangle is created with attributes length and width.

The class attributes are initialized using the __init__ constructor.

In the rectangle class, a method/function is declared to return the area of the rectangle.

class Box

This class is a child of rectangle and it inherits all its attributes and methods,

It has an additional attribute of depth and its constructor is used to initialize it.

The class contains a volume function, that returns the volume and an override function 'area()' that displaces the area from the parent class.

Finally, some instances of both classes are created.

4 0
3 years ago
What is the reason that friction is present in surface to surface contact?
Andrej [43]
One surface is larger than the other surface
3 0
2 years ago
If I had to choose the class I prefer it would be a
dmitriy555 [2]
How about you prefer no class
4 0
3 years ago
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