What is the reason that friction is present in surface to surface contact?

__________________ ensures that each row is uniquely identified by the primary key, which means that a proper search for an exis

klemol [59]

Solution:

Database integrity ensures that each row is uniquely identified by the primary key, which means that a proper search for an existing tuple (row) will always be successful.

Thus the required answer is D

4 0

3 years ago

You should process the tokens by taking the first letter of every fifth word,starting with the first word in the file. Convert t

zhenek [66]

Answer:

See explaination

Explanation:

import java.io.File;

import java.io.IOException;

import java.util.Scanner;

import java.util.StringTokenizer;

public class SecretMessage {

public static void main(String[] args)throws IOException

{

File file = new File("secret.txt");

StringBuilder stringBuilder = new StringBuilder();

String str; char ch; int numberOfTokens = 1; // Changed the count to 1 as we already consider first workd as 1

if(file.exists())

{

Scanner inFile = new Scanner(file);

StringTokenizer line = new StringTokenizer(inFile.nextLine()); // Since the secret.txt file has only one line we dont need to loop through the file

ch = line.nextToken().toUpperCase().charAt(0); // Storing the first character of first word to string builder as mentioned in problem

stringBuilder = stringBuilder.append(ch);

while(line.hasMoreTokens()) { // Looping through each token of line read using Scanner.

str= line.nextToken();

numberOfTokens += 1; // Incrementing the numberOfTokens by one.

if(numberOfTokens == 5) { // Checking if it is the fifth word

ch = str.toUpperCase().charAt(0);

stringBuilder = stringBuilder.append(ch);

numberOfTokens =0;

}

System.out.println("----Secret Message----"+ stringBuilder);

}

5 0

3 years ago

Which of the following topics is too broad for a 10-minute speech? A. classes offered in interior design B. the history of moder

aksik [14]

I would say it is <span> B. the history of modern interior design
Because this subject stretches pretty far into history</span>

3 0

2 years ago

Read 2 more answers

How do programmers recognise patterns, generalise and abstract information

Dima020 [189]

Answer:

Pattern recognition is the process of recognizing patterns by using machine learning algorithm. ... In a typical pattern recognition application, the raw data is processed and converted into a form that is amenable for a machine to use. Pattern recognition involves classification and cluster of patterns

Explanation:

4 0

2 years ago

Determine whether or not the following pairs of predicates are unifiable. If they are, give the most-general unifier and show th

Evgen [1.6K]

Answer:

a) P(B,A,B), P(x,y,z)

=> P(B,A,B) , P(B,A,B}

Hence, most general unifier = {x/B , y/A , z/B }.

b. P(x,x), Q(A,A)

No mgu exists for this expression as any substitution will not make P(x,x), Q(A, A) equal as one function is of P and the other is of Q.

c. Older(Father(y),y), Older(Father(x),John)

Thus , mgu ={ y/x , x/John }.

d) Q(G(y,z),G(z,y)), Q(G(x,x),G(A,B))

=> Q(G(x,x),G(x,x)), Q(G(x,x),G(A,B))

This is not unifiable as x cannot be bound for both A and B.

e) P(f(x), x, g(x)), P(f(y), A, z)

=> P(f(A), A, g(A)), P(f(A), A, g(A))

Thus , mgu = {x/y, z/y , y/A }.

Explanation:

Unification: Any substitution that makes two expressions equal is called a unifier.

a) P(B,A,B), P(x,y,z)

Use { x/B}

=> P(B,A,B) , P(B,y,z)

Now use {y/A}

=> P(B,A,B) , P(B,A,z)

Now, use {z/B}

=> P(B,A,B) , P(B,A,B}

Hence, most general unifier = {x/B , y/A , z/B }

b. P(x,x), Q(A,A)

No mgu exists for this expression as any substitution will not make P(x,x), Q(A, A) equal as one function is of P and the other is of Q

c. Older(Father(y),y), Older(Father(x),John)

Use {y/x}

=> Older(Father(x),x), Older(Father(x),John)

Now use { x/John }

=> Older(Father(John), John), Older(Father(John), John)

Thus , mgu ={ y/x , x/John }

d) Q(G(y,z),G(z,y)), Q(G(x,x),G(A,B))

Use { y/x }

=> Q(G(x,z),G(z,x)), Q(G(x,x),G(A,B))

Use {z/x}

=> Q(G(x,x),G(x,x)), Q(G(x,x),G(A,B))

This is not unifiable as x cannot be bound for both A and B

e) P(f(x), x, g(x)), P(f(y), A, z)

Use {x/y}

=> P(f(y), y, g(y)), P(f(y), A, z)

Now use {z/g(y)}

P(f(y), y, g(y)), P(f(y), A, g(y))

Now use {y/A}

=> P(f(A), A, g(A)), P(f(A), A, g(A))

Thus , mgu = {x/y, z/y , y/A }.

7 0

3 years ago