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seraphim [82]
2 years ago
7

You are part of the team assigned to implement new software at XYZ Inc. The employees at XYZ Inc. trust the results obtained fro

m the old software, but are cautious about accepting those from the proposed new software. What software implementation strategy would you recommend in this situation to allow users fall-back access to the old system as the new one is implemented
Computers and Technology
1 answer:
Ad libitum [116K]2 years ago
7 0

There are different kinds of software implementation strategy. The software implementation strategy would you recommend in this situation to allow users fall-back access to the old system as the new one is implemented is parallel start up.

  • Parallel running often called parallel start up strategy for system changeover where a new system slowly takes over the roles of the older system even when both systems operate.

This conversion often occur when the technology of the old system is outdated and as such a new system is needed to be installed to replace the old one.

The parallel running phase is the act of changing a fragment of business information technology operation to a new system.

Learn more about Parallel start up from

brainly.com/question/9343211

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Answer:

He was not allowed on a phone of computer after being arrested.

Explanation:

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What is the use of ROM chip in computer system?​
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It will be elisa who will get to it
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3 years ago
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What is the output of the following program? #include using namespace std; class TestClass { public: TestClass(int x) { cout &lt
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Answer:

An error will be occurred here. In C++ a function must be like

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4 0
3 years ago
1. Print out the string length of s1 2. Loop through characters in s2 with charAt() and display reversed string 3. Compare s2, s
konstantin123 [22]

Answer:

See explaination

Explanation:

public class StringLab9 {

public static void main(String args[]) {

char charArray[] = { 'C', 'O', 'S', 'C', ' ', '3', '3', '1', '7', ' ', 'O', 'O', ' ', 'C', 'l', 'a', 's', 's' };

String s1 = new String("Objected oriented programming language!");

String s2 = "COSC 3317 OO class class";

String s3 = new String(charArray);

// To do 1: print out the string length of s1

System.out.println(s1.length());

// To do 2: loop through characters in s2 with charAt and display reversed

// string

for (int i = s2.length() - 1; i >= 0; --i)

System.out.print(s2.charAt(i));

System.out.println();

// To do 3: compare s2, s3 with compareTo(), print out which string (s2 or s3)

// is

// greater than which string (s2 or s3), or equal, print the result out

if (s2.compareTo(s3) == 0)

System.out.println("They are equal");

else if (s2.compareTo(s3) > 0)

System.out.println("s2 is greater");

else

System.out.println("s3 is greater");

// To do 4: Use the regionMatches to compare s2 and s3 with case sensitivity of

// the first 8 characters.

// and print out the result (match or not) .

if (s2.substring(0, 8).compareTo(s3.substring(0, 8)) == 0)

System.out.println("They matched");

else

System.out.println("They DONT match");

// To do 5: Find the location of the first character 'g' in s1, print it out

int i;

for (i = 0; i < s2.length(); ++i)

if(s2.charAt(i)=='g')

break;

System.out.println("'g' is present at index " + i);

// To do 6: Find the last location of the substring "class" from s2, print it

// out

int index = 0, ans = 0;

String test = s2;

while (index != -1) {

ans = ans + index;

index = test.indexOf("class");

test = test.substring(index + 1, test.length());

}

System.out.println("Last location of class in s2 is: " + (ans + 1));

// To do 7: Extract a substring from index 4 up to, but not including 8 from

// s3, print it out

System.out.println(s3.substring(4, 8));

} // end main

} // end class StringLab9

7 0
3 years ago
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