A higher frequency than the analog cell phone.
Answer:
hi your question lacks the necessary matrices attached to the answer is the complete question
1024 bytes
Explanation:
A) The minimum size of the cache to take advantage of blocked execution
The minimum size of the cache is approximately 1 kilo bytes
There are 128 elements( 64 * 2 ) in the preceding simple implementation and this because there are two matrices and every matrix contains 64 elements .
note: 8 bytes is been occupied by every element therefore the minimum size of the cache to take advantage of blocked execution
= number of elements * number of bytes
= 128 * 8 = 1024 bytes ≈ 1 kilobytes
Your answer is false :)
I hope this helps! :)
If an event occurs, the agent logs details regarding the event. what is this event called GET.
The information in the agent log file is known to be the beginning of the log file, which is stated to show the agent's launch and handling of the services and configuration settings.
Keep in mind that the agent log also contains a history of the activities performed by the agent during runtime, along with any errors, and that it is utilised to investigate deployment issues.
As a result, if an event happens, the agent logs information about it. What is this GET event, exactly?
The agent monitoring services' startup and configuration settings are displayed at the log file's beginning. The sequence of agent runtime activity and any observed exceptions are also included in the agent log.
Learn more about agent logs:
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