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Nostrana [21]
3 years ago
11

What is the value of f(3) when f(x) =4x+1

Mathematics
2 answers:
Novosadov [1.4K]3 years ago
8 0

Answer: 13

<u>Step-by-step explanation:</u>

f(x) = 4x + 1

f(3) = 4(3) + 1

     = 12 + 1

     = 13

Makovka662 [10]3 years ago
3 0

f(x) = 4x + 1 \\ f(3) = 4(3) + 1 \\  = 12 + 1 \\  = 13
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quester [9]

Solution :

Let $v_0$ be the unit vector in the direction parallel to the plane and let $F_1$ be the component of F in the direction of v_0 and F_2 be the component normal to v_0.

Since, |v_0| = 1,

$(v_0)_x=\cos 60^\circ= \frac{1}{2}$

$(v_0)_y=\sin 60^\circ= \frac{\sqrt 3}{2}$

Therefore, v_0 = \left

From figure,

|F_1|= |F| \cos 30^\circ = 10 \times \frac{\sqrt 3}{2} = 5 \sqrt3

We know that the direction of F_1 is opposite of the direction of v_0, so we have

$F_1 = -5\sqrt3 v_0$

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The unit vector in the direction normal to the plane, v_1 has components :

$(v_1)_x= \cos 30^\circ = \frac{\sqrt3}{2}$

$(v_1)_y= -\sin 30^\circ =- \frac{1}{2}$

Therefore, $v_1=\left< \frac{\sqrt3}{2}, -\frac{1}{2} \right>$

From figure,

|F_2 | = |F| \sin 30^\circ = 10 \times \frac{1}{2} = 5

∴  F_2 = 5v_1 = 5 \left< \frac{\sqrt3}{2}, - \frac{1}{2} \right>

                   $=\left$

Therefore,

$F_1+F_2 = \left< -\frac{5\sqrt3}{2}, -\frac{15}{2} \right> + \left< \frac{5 \sqrt3}{2}, -\frac{5}{2} \right>$

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3 0
2 years ago
I need help with geometry
swat32

Answer:

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Step-by-step explanation:

Set up a proportion:

x/1.5=10/2.5

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Hope this helps!

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2 years ago
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barxatty [35]

Answer:

Step-by-step explanation:

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- - - Jhs

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Primary - - - - - - - 49 - - - - - - 51 - - - - - - 100%

Jhs - - - - - - - - - - 56 - - - - - - 44. - - - - - - 100%

With the information above,

Primary Dropout percentage:

BOYS : [49 / (49 +51)] × 100.= 49%

GIRLS : [51 / (49 +51)] × 100.= 51%

Jhs: Dropout percentage

BOYS : [56 / ( 56 + 44) × 100 = 56%

GIRLS : [44 / (44 +56)] × 100.= 44%

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3 years ago
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Answer:

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X-7 < -3
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