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morpeh [17]
3 years ago
13

If bd is both the altitude and median of abc then abs is

Mathematics
1 answer:
AVprozaik [17]3 years ago
4 0

Answer:

isosceles

Step-by-step explanation:

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What is the distance between the y-intercepts of the lines? Adding a picture please help
DerKrebs [107]

The equation of a line is:

y = mx + c

The m is the gradient of the line, and the c is the y-intercept of the line

That means that the y-intercept of [y = -4x + 3]  is 3

and the y-intercept of [y = -4x + 4] is 4

So the distance between the two y-intercepts is:

4 - 3 = <u>1</u>

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2 years ago
Two numbers have an absolute value of 37. Which of the two number is farther from 1 on the number line
Brrunno [24]

If I understand what you're saying. It would be the absolute value of -37, which is 37. Also, the absolute value of 37 is 37.

3 0
2 years ago
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Divide using long division. 6x^3+4x^2+3x+2/ 3x+2
12345 [234]

Answer: 2x² + 1

<u>Explanation:</u>

          <u>  2x²  +  0x  +  1     </u>

3x + 2 ) 6x³ + 4x² + 3x + 2

         - <u>(6x³ + 4x²</u>)    ↓     ↓

                                3x + 2

                             - <u>(3x + 2)</u>

                                        0

5 0
3 years ago
What is the equation of the line ?
Zielflug [23.3K]

Answer:

y = -2x + 7

Step-by-step explanation:

tbh too lazy to explain

8 0
3 years ago
Which is the equation of a hyperbola centered at the origin with x-intercept +\- 3 and asymptote y=2x
Radda [10]

Answer:

{\dfrac{x^{2}}{9} - \dfrac{y^{2}}{36} = 1}

Step-by-step explanation:

The hyperbola has x-intercepts, so it has a horizontal transverse axis.

The standard form of the equation of a hyperbola with a horizontal transverse axis is  \dfrac{(x - h)^{2}}{a^{2}} - \dfrac{(y - k)^{2}}{b^{2}} = 1

The center is at (h,k).

The distance between the vertices is 2a.

The equations of the asymptotes arey = k \pm \dfrac{b}{a}(x - h)

1. Calculate h and k. The hyperbola is symmetric about the origin, so  

h = 0 and k = 0

2. For 'a': 2a = x₂ - x₁ = 3 - (-3) = 3 + 3 = 6

a = 6/2 = 3  

3. For 'b': The equation for the asymptote with the positive slope is  

y = k + \dfrac{b}{a}(x - h) = \dfrac{b}{a}x

Thus,  asymptote has the slope of

\begin{array}{rcl}m& =& \dfrac{b}{a}\\\\2& =& \dfrac{b}{3}\\\\b& =& \mathbf{6}\end{array}

4.  The equation of the hyperbola is

\large \boxed{\mathbf{\dfrac{x^{2}}{9} - \dfrac{y^{2}}{36} = 1}}

The attachment below represents your hyperbola with x-intercepts at ±3 and asymptotes with slope ±2.

7 0
2 years ago
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