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Tamiku [17]
3 years ago
12

When conducting a survey, it is important to use a random sample:to get a significant result.to avoid bias and to get a represen

tative sample.so that we can make causal conclusions.to ensure truthful answers to the survey's questions.none of the above.
Mathematics
1 answer:
AleksAgata [21]3 years ago
8 0

Answer: to avoid bias and to get a representative sample

Step-by-step explanation:

A random sample is useful for:

Avoid bias: if you have a selected sample, all of the selected individuals may have some common factor (same age group, same salary rage, same political ideology) so the sample may be kinda biased, this is something that you may want to avoid.

All the other options can not be ensured by any method, you survey, even with a random sample, may have no significant result, and you can not ensure that the surveyed people will answer truthfully.

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A cylindrical can of cat food has a diameter of 3.5 inches and a height of 1.25 inches A second brand of cat food is packaged in
UNO [17]
So..Volume of a cylinder = pi(r)^2 x Height
The first can has a radius of 1.75 (3.5/2) and a height of 1.25 inches..put that in the formula and you'll get the volume of the first cylinder ~ 12.02 
Do the same thing with the second cylinder and you'll get ~5.65 as the volume. 
Now calculate the difference between the two by simply subtracting the two volumes and the difference would  approximately be 6.37 
hope this helps! :)
5 0
3 years ago
Delta math help? I'm stuck please this is very urgent!!!
Airida [17]

Answer:

the vertex is (-7,-90)

the focus is ( -7, -359/4)= (-7,-89.75)

semi-axis length; 1/4=0.25

focal parameter: 1/2=0.5

eccentricity;1

directrix: y=-361/4

Step-by-step explanation:

4 0
3 years ago
Read 2 more answers
A company manufactures 2,000 units of its flagship product in a day. The quality control department takes a random sample of 40
shepuryov [24]

Answer:

B

Step-by-step explanation:

The recommended sample size n for point estimates is:

n = NX / (N + X - 1)

where N is the population size, and X is defined as:

X = Z² p (1 - p) / E²

where Z is the critical value, p is the sample proportion, and E is the margin of error.

Assume a confidence level of level of 95% and a margin of error of 5%.

α = 0.05, Z(α/2) = 1.96

E = 0.05

Of the 40 units tested, 2 had lifespans less than 26 days.  So the proportion is:

p = 2/40 = 0.05

Therefore:

X = (1.96)² (0.05) (1 - 0.05) / (0.05)²

X = 73

Given N = 2000:

n = (2000) (73) / (2000 + 73 - 1)

n = 70.45

Rounding, the recommended sample size is 70.

5 0
3 years ago
Read 2 more answers
Solve 0.05p-0.02(5-2p)=0.05(p-2)-0.12
Montano1993 [528]
0.05p-0.02(5-2p)=0.05(p-2)-0.12 

0.05p-0.02(5-2p)=0.05(p-2)-0.12:p 


0.05p-0.1+0.04p=0.05p-0.1-0.12
 
  |Expand \ the \ equation| 

0.09p-0.1=0.05p-0.1-0.12
 
 

0.09p-0.1=0.05p-0.22 


0.09p-0.1-0.05p=-0.22
 

  |Subtract \ 0.05p \ from \ both \ sides| 


0.04p-0.1=-0.22
 
 


0.04p=-0.22+0.1
 
  |Add \ 0.1 \ to \ both \ sides| 


0.04p=-0.12
 
 

0.04p/0.04=-0.12/0.04
  |Divide \ both \ sides \ by \ 0.04| 

p=-3 

\star \ Hence \ Solved
8 0
3 years ago
A large university accept 40% of the students who apply. Of the students the university accept, 25% actually enroll. If 10,000 s
sukhopar [10]

Answer:

2,500

Step-by-step explanation:

Multiply 10,000 with 1/4 and since 1/4 equals to 25%.

10,000 x 1/4 = 2,500

Your answer is there and I hope this helps!

6 0
2 years ago
Read 2 more answers
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