All categories

3 years ago

Choose the correct sum of the polynomials (6x3 − 8x − 5) + (3x3 + 6x + 2). 9x3 − 2x − 3 3x3 + 2x + 3 3x3 − 2x − 3 9x3 + 14x + 3

Mathematics

2 answers:

oksian1 [2.3K]3 years ago

7 0

Answer:

Option A. ( 9x³ - 2x - 3 )

Step-by-step explanation:

Given polynomials are ( 6x³ - 8x - 5 ) and ( 3x³ + 6x + 2)

We have to find the sum of these polynomials

( 6x³ - 8x - 5 ) + ( 3x³ + 6x + 2)

We will collect the similar terms first.

6x³ - 8x - 5 + 3x³ + 6x = 2

= ( 6x³ + 3x³ ) + ( 6x - 8x ) + ( 2 - 5 )

= ( 9x³ - 2x - 3 )

Option A. ( 9x³ - 2x - 3 ) is the correct option.

stiks02 [169]3 years ago

6 0

9x3 - 2x - 3
Simplify 6x3-8x-5 + 3x3+6x+2

You might be interested in

A discuss moves from P1 (4,8) to P2 (15,17). What is the lincar displacement in the horizontal and vertical directions? What is

Yakvenalex [24]

Answer:

The horizontal displacement is 11 units, the vertical displacement is 9 units, and the projection angle is 39.3 degrees.

Step-by-step explanation:

We can start using the definition of displacement in one dimension between any 2 points which is the difference between them, so we have

$\Delta s = s_2-s_1$

And apply it to get the horizontal and vertical displacements.

Once we have found them, we can use trigonometric functions to find the projection angle with respect the horizontal.

Linear displacements.

Using the definition of displacement, we can write the horizontal displacement as

$\Delta x = x_2-x_1$

So we can use the given points $P1:(x_1,y_2) \text{ and } P_2: (x_2,y_2)$ on the displacement formula

$\Delta x = 15-4\\\Delta x = 11$

In the same manner we can look at the y components of those points to find the vertical displacement

$\Delta y = 17-8\\\Delta y =9$

Thus the horizontal displacement is 11 units and the vertical displacement is 9 units.

Projection angle.

The projection angle with respect the horizontal is the angle that is made between the line that connects the points P1 and P2 and the horizontal, so we can use the linear displacements previously found to write

$\tan(\theta) = \cfrac{\Delta y}{\Delta x}$

Solving for the angle we get

$\theta = \tan^{-1}\left(\cfrac{\Delta y}{\Delta x}\right)$

Replacing values

$\theta = \tan^{-1}\left(\cfrac{9}{11}\right)$

Which give us

$\theta = 39.3^\circ$

So the projection angle is 39.3 degrees.

7 0

3 years ago

Please help asap

FromTheMoon [43]

Answer: $9

Step-by-step explanation:

10 percent of 9 or 90 broken into 10 parts is 9 also 90 divided by 10 is 9

3 0

3 years ago

When we test Upper H 0: muequals0 against Upper H Subscript a: mugreater than0, we get a P-value of 0.03. a. What would the

Anastasy [175]

Answer:

(a) The null hypothesis will be rejected.

(b) Type I error

Step-by-step explanation:

The hypothesis provided is:

$H_{0}: \mu = 0\\ H_{a} : \mu > 0$

The p-value of the test obtained is 0.03

(a)

Decision rule for hypothesis testing, based on p-value, states that if the p-value is less than the significance level (α) then the null hypothesis is rejected and vice versa.

The significance level is α = 0.10

Then,

$p-value = 0.03 < \alpha = 0.10$

Thus, the null hypothesis will be rejected.

Conclusion:

The null hypothesis is rejected stating that the value of μ is more than 0.

(b)

If the decision in (a) is an error, i.e. the null hypothesis is rejected when in fact it is true, this type of error is known as type I error.

(c)

The significance level is α = 0.01

Then,

$p-value = 0.03 > \alpha = 0.01$

Thus, the null hypothesis will not be rejected.

Conclusion:

The null hypothesis was not rejected stating that the value of μ is 0.

If this decision is an error, i.e. the null hypothesis was not rejected when in fact it is false, this type of error is known as type II error.

3 0

3 years ago

The LCD for 1 over 7 and 1 over 8 is

asambeis [7]

The least common denominator would be 56. Hope I helped you!

7 0

3 years ago

35,520 divided by 96

Vlada [557]

The answer would be 370

3 0

3 years ago