Answer:
The probability that a person with restless leg syndrome has fibromyalgia is 0.1833.
Step-by-step explanation:
Denote the events as follows:
<em>F</em> = a person with fibromyalgia
<em>R</em> = a person having restless leg syndrome
The information provided is as follows:
P (R | F) = 0.33
P (R | F') = 0.03
P (F) = 0.02
Consider the tree diagram attached below.
Compute the probability that a person with restless leg syndrome has fibromyalgia as follows:

Thus, the probability that a person with restless leg syndrome has fibromyalgia is 0.1833.