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LUCKY_DIMON [66]
3 years ago
11

Enter the data to create a histogram. Then check all that apply.

Mathematics
2 answers:
fomenos3 years ago
8 0

Answer:

Enter the data to create a histogram. Then check all that apply.

A 1-column table with 10 rows. Column 1 is labeled runs with entries 1, 7, 1, 6, 1, 2, 8, 6, 8, 0.

The histogram has 1 cluster.

The histogram has 2 clusters.

The histogram has 1 peak.

The histogram has 4 peaks.

The histogram has 0 frequency from 4-5.Step-by-step explanation:

Ksju [112]3 years ago
4 0

Answer:

B,C,E

Step-by-step explanation:

The histogram has 2 cluster

The histogram 1 peak

The histogram has 0 frequency from 4-5

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Flura [38]
Surface Area (SA) of a Cylinder formula:
SA = 2*pi*r*h+2*pi*r^2
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6 0
3 years ago
zoey made 6 3/4 of fruit for a picnic. at the picnic, they ate 1/3 of the fruit sala. how much fruit salad did they eat?
ira [324]
1/3 of 6 3/4....." of " means multiply....turn mixed number to improper fraction
1/3 * 27/4 = 27/12 = 2 1/4 <==
5 0
3 years ago
10. Three kinds of teas are worth $4.60 per pound, $5.75 per pound, and $6.50 per pound. They are to be
zepelin [54]

Answer:

The mass of the $4.60/lb tea that should be used in the mixture is 10 lb

The mass of the $5.75/lb tea that should be used in the mixture is 8 lb

The mass of the $6.50/lb tea that should be used in the mixture is 2 lb

Step-by-step explanation:

The parameters of the question are;

The worth of the three teas are

Tea A = $4.60/lb

Tea B = $5.75/lb

Tea C = $6.50/lb

The mass of the mixture of the three teas = 20 lb

The worth of the mixture of the three teas = $5.25 per pound = $5.25/lb

The amount of the $4.60 in the mixture = The sum of the amount of the other two teas

Therefore, given that the mass of the mixture = 20 lb, we have in the mixture;

The mass of tea A + The mass of Tea B + The mass of Tea C = 20 lb

The mass of tea A = The mass of Tea B + The mass of Tea C

Therefore;

The mass of tea A + The mass of tea A = 20 lb

2 × The mass of tea A in the mixture = 20 lb

The mass of tea A in the mixture = 20 lb/2 = 10 lb

The mass of tea A in the mixture = 10 lb

The mass of Tea B + The mass of Tea C = The mass of tea A = 10 lb

The mass of Tea B + The mass of Tea C = 10 lb

The mass of Tea B  = 10 lb - The mass of Tea C

Where the mass of Tea C in the mixture = x, we have;

The mass of Tea B in the mixture = 10 lb - x

The cost of the 10 lb of tea A = 10 × $4.60 = $46.0

The worth of the tea mixture = 20 × $5.25 = $105

The worth of the remaining 10 lb of the mixture comprising of tea A and tea B is given as follows;

The worth of Tea B + The worth of Tea C in the mixture = $105.00 - $46.00 = $59.00

Therefore, we have;

x lb × $6.50/lb + (10 - x) lb × $5.75/lb = $59.00

x × $6.50 - x × $5.75 + $57.50 = $59.00

x × $0.75 = $59.00 -  $57.50 = $1.50

x =  $1.50/$0.75 = 2 lb

∴ The mass of Tea C in the mixture = 2 lb

The mass of Tea B in the mixture = 10 lb - x = 10 lb - 2 lb = 8 lb

The mass of Tea B in the mixture = 8 lb

Therefore, since we have;

Tea A = $4.60/lb

Tea B = $5.75/lb

Tea C = $6.50/lb

The mass of tea A in the mixture = 10 lb

The mass of tea B in the mixture = 8 lb

The mass of tea C in the mixture = 2 lb, we find;

The mass of the $4.60/lb tea that should be used in the mixture = 10 lb

The mass of the $5.75/lb tea that should be used in the mixture = 8 lb

The mass of the $6.50/lb tea that should be used in the mixture = 2 lb.

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2 years ago
Find the measure of FGH
ololo11 [35]
Fgh is 144 because 360 - 216 = 144
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2 years ago
{(-1, -1) (3.8) (2, 4)(2, 3), (7. -7) }
vodka [1.7K]

jStep-by-step explanation:

I cannot see the question

4 0
2 years ago
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