Answer: solutions found
Step by Step Solution
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Reformatting the input :
Changes made to your input should not affect the solution:
(1): "u2" was replaced by "u^2". 2 more similar replacement(s).
Non Integer Exponent Not Yet Implemented
........ V
(x^3x^u^2032+3x-2)0x-2;ox+2;ox-4ox+1;(*^u^2032-x+1)
Non Integer Exponent Not Yet Implemented
.......................................... V
(x^3x^u^2032+3x-2)0x-2;ox+2;ox-4ox+1;(*^u^2032-x+1)
Consecutive Operators
................................................ V
(x^3*x^u^2032+3*x-2)0*x-2;o*x+2;o*x-4*o*x+1;(*^u^2032-x+1)
Program Execution Terminated
Tiger was not able to solve for your input:(x3x^u2032+3x-2)0x-2;ox+2;ox-4ox+1;(*^u2032-x+1)
Step-by-step explanation:
Hello there!
4(3x - 11) + 23 = 5x - 14
Apply the distributive property to 4(3x - 11)
4(3x) + 4(-11)
12x - 44
We now have:
12x - 44 + 23 = 5x - 14
Combine like-terms on the left-hand side of the equation.
-44 + 23 = -21
12x - 21 = 5x - 14
Get x on one side by subtracting 5x from both sides..
12x - 5x = 7x
5x - 5x = 0
7x - 21 = -14
Add 21 to both sides to isolate 7x.
-21 + 21 = 0
-14 + 21 = 7
7x = 7
Divide both sides by 7 to solve for x.
7x / 7 = x
7 / 7 = 1
We are now left with the following solution:
x = 1
I hope this helps!
Answer:
Step-by-step explanation:
<u>Let the numbers be x and y</u>
<u>Then, substituting y:</u>
Correct option is 1)
Answer: a > 4
<u>Step-by-step explanation:</u>
-5 + a > -1
<u>+5 </u> <u>+5 </u>
a > 4
Graph: 4 o-----------→
Interval Notation: (4, ∞)
Answer:
a) 3,6,9,12,15,..
b) Common Ratio is 3
c) Recursive Formula : aₙ= aₙ₋₁ + d where a₁=3 and d= 3
Step-by-step explanation:
a) Create your own arithmetic sequence. Write out the first 3 terms.
Consider the sequence: 3,6,9,12,15,..
a₁ = 3
a₂ = 6
a₃ = 9
b) What is the common difference of your sequence?
6-3 = 3
9-6 = 3
12 -9 =3
So, common difference is 3
c) Write the recursive formula representing your sequence.
a₁ = 3
a₂ = aₙ₋₁ + d
= a₁ + d
= 3+ 3 = 6
a₃ = aₙ₋₁ + d
= a₂ + d
= 6+3 = 9
so, recursive formula is aₙ = aₙ₋₁ + d where a₁ = 3 and d= 3
